Search found 12 matches
Thank you guys, Good luck in your preparation as well. @haptas: I would definitely encourage you to take it again, don’t rush it however. The question repetition was a problem for me as well, however I will link it to how did I drive additional benefits from the previous attempts, but please note ...
- by ahmad.kadry
Wed Dec 02, 2009 2:16 am- Forum: I just Beat The GMAT!
- Topic: Finally a 710 (V 39,Q 49) 3rd trial , my lessons learned :)
- Replies: 4
- Views: 2311
Finally a 710 (V 39,Q 49) 3rd trial , my lessons learned :)
Well, I am very please to share with everybody on this forum that I finally got a 710 on the GMAT last week, this has been my third trial and finally I got a satisfying score; I won't detail a study plan, but hoping to help other test takers, I just need to share the SEVEN most significant lessons l...
- by ahmad.kadry
Tue Dec 01, 2009 2:06 pm- Forum: I just Beat The GMAT!
- Topic: Finally a 710 (V 39,Q 49) 3rd trial , my lessons learned :)
- Replies: 4
- Views: 2311
Hi, We have the following facts. - 20 parents - 5 days to choose from (Mo, Tu, We, Th, Fr) - Each parent will select maximum 1 day - More people chose "Mo" than "Tu". - No restriction on the parent/day distribution or the maximum parents per day! - There is a possibility that som...
- by ahmad.kadry
Mon Aug 03, 2009 3:20 am- Forum: Data Sufficiency
- Topic: Parent- Teacher
- Replies: 8
- Views: 2405
Hi tohellandback, You are correct about the distance designation, however, IMO, the distance can be either positive or negative but the absolute value of that distance is only positive. In more details, consider x = 5, a point that is 2 units away from x on the number line can be either "7&quo...
- by ahmad.kadry
Mon Aug 03, 2009 1:05 am- Forum: Data Sufficiency
- Topic: Is x > 0
- Replies: 13
- Views: 1946
Hi tohellandback, You are correct about the distance designation, however, IMO, the distance can be either positive or negative but the absolute value of that distance is only positive. In more details, consider x = 5, a point that is 2 units away from x on the number line can be either "7&quo...
- by ahmad.kadry
Mon Aug 03, 2009 12:57 am- Forum: Data Sufficiency
- Topic: Is x > 0
- Replies: 13
- Views: 1946
Hi tohellandback, You are correct about the distance designation, however, IMO, the distance can be either positive or negative but the absolute value of that distance is only positive. In more details, consider x = 5, a point that is 2 units away from x on the number line can be either "7"...
- by ahmad.kadry
Mon Aug 03, 2009 12:34 am- Forum: Data Sufficiency
- Topic: Is x > 0
- Replies: 13
- Views: 1946
Hi Statement 1: The odd/even rules are: - odd X odd = odd - even x even = even - even x odd = even So basically, if the set involved one even number, the product of all numbers will be even. The only way the product of all numbers to be odd is for the set to contain only odd numbers. The number of o...
- by ahmad.kadry
Sun Aug 02, 2009 8:21 am- Forum: Data Sufficiency
- Topic: M integers
- Replies: 2
- Views: 1122
Hi, You can consider doing that for statement 1. x – y^2 > 0... for inequalities you can add a value to both sides.. so by adding y^2 to both sides: x - y^2 + y^2 > 0 + y^2 x > y^2 Since y^2 is either 0 or positive.. and x > y^2 ..that tells us that: 1 - x must be a positive value 2 - x > y^2 Now.. ...
- by ahmad.kadry
Sun Aug 02, 2009 7:56 am- Forum: Data Sufficiency
- Topic: x>y??
- Replies: 2
- Views: 1439
Hi shahdevine, In my opinion the full solution will look like this. For statement 1, we have A the +ve case and B the -ve case. 1-A: x + 3 = 4x - 3 -> 3x = 6 -> x = 2 1-B: -x - 3 = 4x - 3 -> 5x = 0 -> x = 0 So, statement 1 gives us x = {0,2), however, after solving the absolute value you should vali...
- by ahmad.kadry
Sun Aug 02, 2009 7:37 am- Forum: Data Sufficiency
- Topic: Is x > 0
- Replies: 13
- Views: 1946
Absolute values
Hi, i believe it wasn't meant to set X to a negative value. usually when you solve an absolute value problem, the full expression within the absolute value might equal a positive or a negative value. for example: |3| = |-3| = 3 So in this case: |(x+3)| = |-(x+3)| = x+3, Hence, you will have two case...
- by ahmad.kadry
Sun Aug 02, 2009 7:08 am- Forum: Data Sufficiency
- Topic: Is x > 0
- Replies: 13
- Views: 1946
simplify the numbers
I agree with the above solutions .. that is definitely a primes problem...an easy way to look at this is to put it that way: X = 5^2 = (5 * 5) Y = 3^3 = (3 * 3 * 3) Z = n * 2^5 * 6^2 *7^3 is ... n * (2 * 2 * 2 * 2 * 2) * (2 * 3 * 2 * 3) * (7 * 7) for the first two number X and Y to be factors of the...
- by ahmad.kadry
Thu Jul 02, 2009 2:22 am- Forum: Problem Solving
- Topic: Help with nasty factors problem
- Replies: 3
- Views: 1179
650 (Q 42 / V 37)...planning to retake !
Hi all, First, i would like to thank everybody on this great forum, it really serves a purpose and it is of a great help to anybody who is willing to take the GMAT. I just took my first GMAT yesterday after 2 months of perparation, the total score corresponds to 80 on the percentile rankings but sep...
- by ahmad.kadry
Thu Jun 18, 2009 1:20 am- Forum: I just Beat The GMAT!
- Topic: 650 (Q 42 / V 37)...planning to retake !
- Replies: 1
- Views: 1680