explanation:

first 3 students == a, b, (a+b)/2

4th student == 1/3 [ a+b+ (a+b)/2] = (a+b)/2

a, b, (a+b)/2, (a+b)/2

5th student == 1/4 [ a+b+ (a+b)/2 + (a+b)/2] = (a+b)/2

it goes on... from 3rd student onwards, everyone draws (a+b)/2

to me it seems answer is E

assuming square side = a, Hexagon size = b

a^2 = (3 * sqrt 3)/2 * b^2

=> 4a/6b = 2/3 * sqrt [ (3* sqrt 3) /2)]
or can be put this way: 4a/6b = (sqrt 2)/ 3 * [sqrt ( 3 * sqrt 3)]


its not matching with option A, B, C..

OR, am i doing something wrong?

Thanks Ian for confirming... I just went back and found that it was uploaded years back by Eric http://www.beatthegmat.com/difficult-gmat-math-problems-t78.html?highlight=gmat%20math%20tough%20problems so, I am sure it was overlook... May I request Eric or someone to review and correct if any such i...

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fibbonnaci or anyone, any thoughts on my previous comment....I am trying to clear my doubts...pls help

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