Search found 5 matches
From statement one, you can rearrange it as follows:
(a-b)(a+b)/(a-b) = 6
the top and bottom (a-b) terms cancel out leaving you with:
a+b = 6
therefore 1 is sufficient
for statement 2 you get a+b = +/- 6 which gives you 2 answers and therefore it is not sufficient.
- by deep2002
Mon Feb 02, 2009 6:21 pm- Forum: Data Sufficiency
- Topic: Good hard practice data suffiency question I don't get
- Replies: 1
- Views: 1056
I used the simple formula Total = #A + #B + #C - #(A&B) - #(B&C) - #(C&A) - #(A&B&C) - #(A&B&C) + #not member A,B & C. Last part(not member A,B & C) is what we are interested in.. just put the values and you will get the answer in no time Does this formula always...
- by deep2002
Mon Feb 02, 2009 11:25 am- Forum: Problem Solving
- Topic: SET Theory
- Replies: 4
- Views: 1758
Wouldn't the possible combinations with no restrictions be 5!/1! since there are 4 alternatives? (A,O,L,P)
- by deep2002
Mon Feb 02, 2009 10:25 am- Forum: Problem Solving
- Topic: arrangement. HELP
- Replies: 16
- Views: 3198
So on a test, the only way to answer this is to litearlly take every single situation and analyze it? To try and look at all scenario would be very time consuming...is there another way?
- by deep2002
Mon Feb 02, 2009 10:19 am- Forum: Problem Solving
- Topic: How many allowable codes are there?
- Replies: 9
- Views: 1784
alternative solution: Let X=violet paint weight Let Y=Green paint weight From Violet paint, Blue = 0.3X Red = 0.7X From Green paint, Blue=0.5Y Yellow = 0.5Y the paints are all mixed together: 0.3X + 0.7X + 0.5Y + 0.5Y = 10 X + Y = 10 We also know that 40% of weight is blue in the brown paint, 0.3X +...
- by deep2002
Mon Feb 02, 2009 9:58 am- Forum: Problem Solving
- Topic: let's mix paints for GMAT prep !
- Replies: 9
- Views: 4317