Search found 87 matches
Hey Realanoop (hmmmm....i wonder wat your name could be....its so difficult to guess)
which center were you in?
In was in Mumbai, on 13th itself.
Got a 740 (49, 43)......
- by rajataga
Tue Jan 13, 2009 7:08 am- Forum: I just Beat The GMAT!
- Topic: 760 - Q50 V44
- Replies: 4
- Views: 2457
I agree with the OA..... MUST BE true is used here to denote that the option selected must be true for all possible values of x that can be derived from the given equation. Hence, if we choose A, there are values of x, such that -1 < x < 0, that are not satisfied by option A. Hence, option A would n...
- by rajataga
Sun Jan 11, 2009 1:23 pm- Forum: Problem Solving
- Topic: Xs good one.
- Replies: 16
- Views: 3901
Came across it on 4gmat.com....
Actually very true, the question is kinda worded wrong if u think about the first part...
- by rajataga
Sun Jan 11, 2009 10:47 am- Forum: Problem Solving
- Topic: Probability of once in four
- Replies: 6
- Views: 4321
i guess i know the answer mathematically....
each of these events are exclusive, and the outcome of one doesn't affect the outcome of another.....However, i am not yet convinced about this....
- by rajataga
Sun Jan 11, 2009 8:35 am- Forum: Problem Solving
- Topic: Probability of once in four
- Replies: 6
- Views: 4321
Also, would you consider y=0 as one of the possibilities???
Even though it falls in the given range, y=0 would essentially mean that that edge lies on the X axis itself, and hence not parallel to the X-axis as given in the question.
- by rajataga
Sun Jan 11, 2009 8:26 am- Forum: Problem Solving
- Topic: No. of rectangles
- Replies: 6
- Views: 1672
Thanks Stuart, you are correct.
However, what is the reason that in this scenario, you cannot think of them as 4 exclusive events, and say that if he takes 4 shots at the target, he will hit it atleast once?
- by rajataga
Sun Jan 11, 2009 8:21 am- Forum: Problem Solving
- Topic: Probability of once in four
- Replies: 6
- Views: 4321
Probability of once in four
A man can hit a target once in 4 shots. If he fires 4 shots in succession, what is the probability that he will hit his target?
A. 1
B. 255/256
C. 175/256
D. 1/4
E. 1/2
- by rajataga
Sun Jan 11, 2009 8:07 am- Forum: Problem Solving
- Topic: Probability of once in four
- Replies: 6
- Views: 4321
Now that i write this, i realize why this difference is occurring. each of the points is being taken as unique. Hence, points ABCD could be interchanged by points DABC, and that is being counted as a separate rectangle. However, shouldn't this hold true? would rectangle ABCD be the same as DABC, bec...
- by rajataga
Sun Jan 11, 2009 7:27 am- Forum: Problem Solving
- Topic: No. of rectangles
- Replies: 6
- Views: 1672
5c2 * 5c2 Just a minor correction - 4c2 * 5c2 which is 60. I got this. But when i did it in a slightly different way, i got a different answer. Can you just point out the mistake. Total no. of points in this area = 20 Point A can now take up any of these points. Now, point B, assuming AB is parallel...
- by rajataga
Sun Jan 11, 2009 7:20 am- Forum: Problem Solving
- Topic: No. of rectangles
- Replies: 6
- Views: 1672
No. of rectangles
The coordinates (x,y) of each corners of rectangle ABCD are such that x and are integers and satisfy the equations 1 < x < 6 and -3 < y < -3. The edges of the rectangle are parallel to the X and Y axes. How many distinct rectangles could be formed which would satisfy these requirements?
- by rajataga
Sun Jan 11, 2009 6:05 am- Forum: Problem Solving
- Topic: No. of rectangles
- Replies: 6
- Views: 1672
ch017, wat you were talking about is called 'bisection' that is dividing the line into half.
Intersection is just a common point/s between 2 figures.
- by rajataga
Sat Jan 10, 2009 5:55 am- Forum: Data Sufficiency
- Topic: line intersection??
- Replies: 11
- Views: 4495
Thanks.
I had thought about the same point, but then went ahead with it, thinking that there wasnt a time factor involved.
Thanks again.
- by rajataga
Fri Jan 09, 2009 7:53 am- Forum: Problem Solving
- Topic: Average
- Replies: 7
- Views: 6778
- by rajataga
Fri Jan 09, 2009 5:46 am- Forum: Problem Solving
- Topic: Average
- Replies: 7
- Views: 6778
- by rajataga
Fri Jan 09, 2009 3:07 am- Forum: Problem Solving
- Topic: Average
- Replies: 7
- Views: 6778
- by rajataga
Thu Jan 08, 2009 9:42 am- Forum: Problem Solving
- Topic: LOST
- Replies: 2
- Views: 1469