Search found 11 matches
Veritas redemption
Hi Team,
I have seen the banner on top that says that we can redeem forum points for Veritas exams. I have filled the spreadsheet but haven't received any registration link
Is that offer still valid ?
Regards,
Targt780
- by Targt780
Fri Sep 18, 2020 10:55 am- Forum: GMAT Strategy
- Topic: Veritas redemption
- Replies: 1
- Views: 1583
GMAT OG vs MBA.com
I have the OG book, which has the question bank accessible online through gmat.wiley.com. What is the difference between this portal / question set and the question set available on MBA.com (ex. the free 2 practice tests, and then the purchase packages of 3/4 and 5/6)? The reason I ask: I have the O...
- by Targt780
Tue Sep 15, 2020 8:26 pm- Forum: GMAT Strategy
- Topic: GMAT OG vs MBA.com
- Replies: 1
- Views: 1213
Improve Verbal
Hi Everyone, I have given my GMAT diagnostic test and score a 670 (Q47 V35). I finished the e-GMAT verbal course which helped me improve SC but my CR and RC are up in the air. Would be great if anyone can share how they managed to have that last stride of push to get V>40 I am aiming for a 740+ scor...
- by Targt780
Tue Sep 15, 2020 8:21 pm- Forum: GMAT Strategy
- Topic: Improve Verbal
- Replies: 1
- Views: 1209
Veritas vs Kaplan
Hi Everyone - I wanted to get your opinion / reviews on both veritas and kaplan tests. Which one of them in your opinion was a close representation of the GMAT?
Thanks a lot in advance
- by Targt780
Tue Sep 15, 2020 8:18 pm- Forum: GMAT Strategy
- Topic: Veritas vs Kaplan
- Replies: 0
- Views: 1120
Problem Solving
If s and t are positive integers such that \(\frac{s}{t}=64.12\), which of the following could be the remainder when s is divided by t ?
A. 2
B. 4
C. 8
D. 20
E. 45
Source: OG
- by Targt780
Sat Aug 22, 2020 11:36 am- Forum: Problem Solving
- Topic: Problem Solving
- Replies: 0
- Views: 241
In a small snack shop, the average (arithmetic mean) revenue was $400 per day over a 10-day period. During this period,
Problem Solving
Re: In a small snack shop, the average (arithmetic mean) revenue was $400 per day over a 10-day period. During this peri
Given that Average revenue over a 10 period is 400 Average revenue over the first 6 days is 360 Let the revenue per day be given by D1, D2, .... D10 Converting the above statements into equations we have Statement (2) \(\frac{D_1+D_2+D_3+D_4+D_5+D_6}{6}=360\) Solving it we have \(D_1+D_2+D_3+D_4+D_5...
- by Targt780
Sat Aug 22, 2020 4:00 am- Forum: Problem Solving
- Topic: In a small snack shop, the average (arithmetic mean) revenue was $400 per day over a 10-day period. During this period,
- Replies: 2
- Views: 335
Re: Word Problems
Let the initial number of cookies be x Total weight of the mixture = 600 ounces Since they are identical the weight per cookie will be the same Weight per cookie is \(\frac{600}{x}\) Let the new cookies be y (cookies produced after reducing the weight by 1 ounce) Given that they produced 30 cookies ...
- by Targt780
Sat Aug 22, 2020 3:24 am- Forum: Problem Solving
- Topic: Word Problems
- Replies: 2
- Views: 485
All the widgets manufactured by Company X are stored in two warehouses, A and B. Warehouse A...
Problem Solving
Re: All the widgets manufactured by Company X are stored in two warehouses, A and B. Warehouse A...
Let the number of widgets in Warehouse A be x and Let the number of widgets in Warehouse B be y Given that x=3y (Number of widgets in Warehouse A is 3 times the number of widgets in Warehouse B) Total number of widgets manufactured by the company = x+y= 3y+y = 4y Warehouse A: Number of widgets in th...
- by Targt780
Sat Aug 22, 2020 3:07 am- Forum: Problem Solving
- Topic: All the widgets manufactured by Company X are stored in two warehouses, A and B. Warehouse A...
- Replies: 1
- Views: 269
A cement mixture is composed of 3 elements. By weight, 1/3 of the mixture is sand, 3/5 of the mixture is...
Problem Solving
Re: A cement mixture is composed of 3 elements. By weight, 1/3 of the mixture is sand, 3/5 of the mixture is...
Given that Sand composition in the mixture = \(\frac{1}{3}\) Water composition in the mixture = \(\frac{3}{5}\) Let the gravel composition be x We know that the entire sum of the 3 elements needs to be 1 i.e., \(\frac{1}{3}\) + \(\frac{3}{5}\) + x =1 or x= 1- \(\frac{1}{3}\) - \(\frac{3}{5}\) x = \(...
- by Targt780
Sat Aug 22, 2020 2:55 am- Forum: Problem Solving
- Topic: A cement mixture is composed of 3 elements. By weight, 1/3 of the mixture is sand, 3/5 of the mixture is...
- Replies: 1
- Views: 314
Joan spent $10 to buy at least one piece each of apples and oranges at a store where each apple cost $2 and each orange
Data Sufficiency
Re: Joan spent $10 to buy at least one piece each of apples and oranges at a store where each apple cost $2 and each ora
Let the number of apples be A and the number of oranges be O We know that A>0 and O>0 and since we cannot purchase fractions of fruit we can safely assume that both are A and O are integers Total amount spent = $10 Cost of each apple = $2 Cost of each orange = $1 The question stem translates to 2A+O...
- by Targt780
Sat Aug 22, 2020 2:46 am- Forum: Data Sufficiency
- Topic: Joan spent $10 to buy at least one piece each of apples and oranges at a store where each apple cost $2 and each orange
- Replies: 2
- Views: 379
A fudgemaker has 40 pounds of chocolate, 65% of which is dark chocolate. If she buys 10 more pounds of chocolate, 25%
Problem Solving
Re: A fudgemaker has 40 pounds of chocolate, 65% of which is dark chocolate. If she buys 10 more pounds of chocolate, 25
Initial weight of the chocolate = 40 pounds % of dark chocolate in the initial mixture = 65% Dark chocolate in the initial mixture (pounds) = 65%*40=26 pounds Additional chocolate purchased (Pounds) = 10 pounds % of dark chocolate in the additional purchase = 25% Dark chocolate in the additional cho...
- by Targt780
Sat Aug 22, 2020 2:39 am- Forum: Problem Solving
- Topic: A fudgemaker has 40 pounds of chocolate, 65% of which is dark chocolate. If she buys 10 more pounds of chocolate, 25%
- Replies: 2
- Views: 339