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tn= t1*n+n/2(n-1)*d
t1 = 18 (number of seats on the first row)
n= 27 rows
d =2 (2 seats increased on each row)
tn = 18*27 + 27/2(26)*2
tn = 486+702
tn=1188
- by muthuvelur
Thu Nov 07, 2019 11:05 am- Forum: Data Sufficiency
- Topic: The number of seats in the first row of an auditorium is 18
- Replies: 5
- Views: 6276