Search found 13 matches
The sum of some value from the first row and and some value from the first column is given in the intersection box of these values. So: x+4=1 --> x=-3; y+4=-5 --> y=-9; x+e=-3+e=7 --> e=10; y+e=-9+10=n --> n=1; z+e=z+10=10 --> z=0; z+4=0+4=m --> m=4; m+n=4+1=5m+n=4+1=5. Answer: C.
- by rajeet123
Tue Jun 11, 2019 9:18 am- Forum: Problem Solving
- Topic: In the addition table shown above, what is the value of m +
- Replies: 2
- Views: 802
In the addition table shown above, what is the value of m +
+ x y z
4 1 -5 m
e 7 n 10
f 2 -4 5
In the addition table shown above, what is the value of m + n =?
A. -19
B. 4
C. 5
D. 6
E. 22
- by rajeet123
Tue Jun 11, 2019 9:16 am- Forum: Problem Solving
- Topic: In the addition table shown above, what is the value of m +
- Replies: 2
- Views: 802
Using the symmetry in the numbers involved (All formed using all possible combinations of 1,2,3,4), and we know there are 24 of them. We know there will be 6 each with the units digits as 1, as 2, as 3 and as 4. And the same holds true of the tens, hundreds and thousands digit. The sum is therefore ...
- by rajeet123
Tue Jun 11, 2019 8:57 am- Forum: Problem Solving
- Topic: sum of these 24 integers?
- Replies: 5
- Views: 812
sum of these 24 integers?
1,234
1,243
1,324
.....
....
+4,321
The addition problem above shows four of the 24 different integers that can be formed by using each of the digits 1,2,3,4 exact;y once in each integer. What is the sum of these 24 integers?
A. 24,000
B. 26,664
C. 40,440
D. 60,000
E. 66,660
- by rajeet123
Tue Jun 11, 2019 8:56 am- Forum: Problem Solving
- Topic: sum of these 24 integers?
- Replies: 5
- Views: 812
The numbers must be of the form ABCD13, where ABCD is any four-digit number between 3247 and 4585 inclusive.
ABCD cannot be 4586, as 458,613>458,600.
Therefore, the total number is 4585 - 3247 + 1 = 1339.
Answer E
- by rajeet123
Tue Jun 11, 2019 8:55 am- Forum: Problem Solving
- Topic: How many integers between
- Replies: 3
- Views: 1141
How many integers between
How many integers between 324,700 and 458,600 have tens digit 1 and units digit 3?
A. 10,300
B. 10,030
C. 1,353
D. 1,352
E. 1,339
- by rajeet123
Tue Jun 11, 2019 8:54 am- Forum: Problem Solving
- Topic: How many integers between
- Replies: 3
- Views: 1141
In the correctly worked addition problem shown
AB
+BA
-----------
AAC
In the correctly worked addition problem shown, where the sum of the two-digit positive integers AB and BA is the three-digit integer AAC, and A, B, and C are different digits, what is the units digit of the integer AAC?
A. 9
B. 6
C. 3
D. 2
E. 0
- by rajeet123
Tue Jun 11, 2019 8:52 am- Forum: Problem Solving
- Topic: In the correctly worked addition problem shown
- Replies: 3
- Views: 1087
Given: 15<x(x+1)<200. Now, it's better to test the answer choices here rather than to solve: If x=3 then x(x+1)=12<15 --> discard A and B; If x=4 then x(x+1)=20>15 --> so, the least value is 4, discard E. Test for the largest value: if x=14 then x(x+1)=14*15=210>200 --> discard D. Answer: C. Else yo...
- by rajeet123
Tue Jun 11, 2019 8:49 am- Forum: Problem Solving
- Topic: In a certain deck of cards
- Replies: 3
- Views: 649
In a certain deck of cards
In a certain deck of cards, each card has a positive integer written on it, in a multiplication game a child draws a card and multiplies the integer on the card with the next large integer. If the each possible product is between 15 and 200, then the least and greatest integer on the card would be A...
- by rajeet123
Tue Jun 11, 2019 8:49 am- Forum: Problem Solving
- Topic: In a certain deck of cards
- Replies: 3
- Views: 649
M is the sum of the reciprocals of the consecutive integers from 201 to 300, inclusive. Which of the following is true? (A) 1/3 < M < 1/2 (B) 1/5 < M < 1/3 (C) 1/7 < M < 1/5 (D) 1/9 < M < 1/7 (E) 1/12 < M < 1/9 Given that M=1201+1202+1203+...+1300M=1201+1202+1203+...+1300. Notice that 1/201 is the l...
- by rajeet123
Tue Jun 11, 2019 8:47 am- Forum: Problem Solving
- Topic: M is the sum of the reciprocals
- Replies: 2
- Views: 462
M is the sum of the reciprocals
M is the sum of the reciprocals of the consecutive integers from 201 to 300, inclusive. Which of the following is true?
(A) 1/3 < M < 1/2
(B) 1/5 < M < 1/3
(C) 1/7 < M < 1/5
(D) 1/9 < M < 1/7
(E) 1/12 < M < 1/9
- by rajeet123
Tue Jun 11, 2019 8:47 am- Forum: Problem Solving
- Topic: M is the sum of the reciprocals
- Replies: 2
- Views: 462
A certain library assesses fines for overdue books as follows. On the first day that a book is overdue, the total fine is $0.10. For each additional day that the book is overdue, the total fine is either increased by $0.30 or doubled, whichever results in the lesser amount. What is the total for a b...
- by rajeet123
Tue Jun 11, 2019 8:45 am- Forum: Problem Solving
- Topic: A certain library
- Replies: 3
- Views: 722
A certain library
A certain library assesses fines for overdue books as follows. On the first day that a book is overdue, the total fine is $0.10. For each additional day that the book is overdue, the total fine is either increased by $0.30 or doubled, whichever results in the lesser amount. What is the total for a b...
- by rajeet123
Tue Jun 11, 2019 8:44 am- Forum: Problem Solving
- Topic: A certain library
- Replies: 3
- Views: 722