Search found 33 matches
Increase in mean value of a set has no direct relation with the increase in median value of the set. Here, we are given the increase in the mean value but we don’t know if the increase is because of change in just 1 value of because of the change in all values. Hence, we can’t determine the chan...
- by masoom j negi
Fri Dec 21, 2018 9:08 pm- Forum: Problem Solving
- Topic: Median - word problem
- Replies: 7
- Views: 3277
The set contains 1-6 elements. A. Consider a set {0, 0 ,6}. Here, mean = 2 and median = 0. B. Consider a set { x }. Here, mean = x and median = x C. Consider a set {-1, -1, 5}. Here mean(x) = 1 and median = -1= -x D.Consider a set {1, 1, 1}. Here mean = 1, y = 3 and median = 1 = y/3. E. T is a set o...
- by masoom j negi
Fri Dec 21, 2018 9:07 pm- Forum: Problem Solving
- Topic: Median of set T
- Replies: 9
- Views: 3349
The function defines that the terms in Set R are in A.P. with common difference 3. Statement 1.We can’t determine the median of an A.P. with just its first term and Common difference. Last term or the total no of terms is also required. Hence, Insufficient. Statement 2. In A.P. the mean of the ser...
- by masoom j negi
Fri Dec 21, 2018 9:06 pm- Forum: Problem Solving
- Topic: mgmat 2
- Replies: 11
- Views: 5887
Any number that will be farthest from the mean of the set will change the standard deviation the most. Here mean of the set is 18/4 = 4.5. Since we have to increase the standard deviation we can’t take any value that is less than the mean. So , 1 and 3 are not acceptable. From 6, 8 and 14, clearly...
- by masoom j negi
Fri Dec 21, 2018 9:03 pm- Forum: Problem Solving
- Topic: Standard Deviation- Manhattan
- Replies: 6
- Views: 6387
11Y will be even if Y is even. Y = product of all elements in the set. There is no even no in the set X. So, ‘k’ should be even to make y even. There is only one even prime no i.e. 2. So, k = 2 The set X becomes {2, 3, 7, 11, 17, 19}. Range of the set = highest element – lowest element = 19 â€...
- by masoom j negi
Fri Dec 21, 2018 8:58 pm- Forum: Problem Solving
- Topic: Range Problem.,...
- Replies: 6
- Views: 2369
Statement 1. N = ay2 (y is a prime number) N has different value for y = 3, 5, 7 etc. Hence, Insufficient. Statement 2. y4 is a two digit odd integer. y= 3. But we don’t know the relation between ‘n’ and ‘y’ in statement 2. Hence, Insufficient. Statement 1 & 2 together. Using the resul...
- by masoom j negi
Fri Dec 21, 2018 8:57 pm- Forum: Data Sufficiency
- Topic: Sum of the digits of the positive integer n where n < 99
- Replies: 4
- Views: 3049
x + y = 77 eq(1) Statement 1. x = y + 1 eq(2) Using eq(1) and eq(2), we get, X = 39 and y = 38. So, xy = 1482. Hence, Sufficient. Statement 2. X = 10a + b Y = 10a + c 10a + b + 10a + c = 77 20a + b + c= 77( where a, b ,c are single digits) This is possible only if (a, b, c) = (3, 8, 9) or (3, 9, 8) ...
- by masoom j negi
Fri Dec 21, 2018 8:55 pm- Forum: Data Sufficiency
- Topic: The sum of positive integers x and y is 77, what is the
- Replies: 3
- Views: 946
m + n will be odd if one of them is odd. Statement 1. m = p2 + 4p + 4 = (p + 2)2 So, m is even if p is even and m is odd if p is odd. But we can’t say anything about m+n. Hence, Insufficient. Statement 2. n = p2 + 2m + 1. 2m is even because it is a multiple of 2. P2 + 1 will be even if p is odd an...
- by masoom j negi
Fri Dec 21, 2018 8:54 pm- Forum: Data Sufficiency
- Topic: If m, n, and p are integers, is m + n odd?
- Replies: 4
- Views: 1726
Statement 1. 5x – 4y is even i.e. 5x – 4y = 2k Difference of two numbers is even if either both of them are odd or both of them are even. Here, 4y is always even. So, 5x is also even. Since 5x is even, we can say that x is even. Now, xy will be even because the product of an even no with any pos...
- by masoom j negi
Fri Dec 21, 2018 8:52 pm- Forum: Data Sufficiency
- Topic: Product XY
- Replies: 4
- Views: 1336
Statement 1. p/4 is a prime no. i.e. p = 4k where k is a prime no. So, p could be anything like 8, 12, 20,……… Hence, Insufficient. Statement 2. P = 3a P could be any positive integer. Hence, Insufficient. Statement 1 & 2 together. P = 4k where k is a prime no and p = 3a So, k = 3. Hence, P...
- by masoom j negi
Fri Dec 21, 2018 8:51 pm- Forum: Data Sufficiency
- Topic: If p is a positive integer...
- Replies: 8
- Views: 5892
There is only 1 even prime no i.e. 2.
So y = 4k and x = 4
Then xy = 44k will have a unit digit of 6 because even powers of 4 always have unit digit 6.
- by masoom j negi
Fri Dec 21, 2018 8:48 pm- Forum: Problem Solving
- Topic: x^y
- Replies: 9
- Views: 2426
Let d = a.bcdef 100th digit of a.bcdef is c Statement 1. 10d = ab.cdef So, 10th digit of ab.cdef = c = 7 Hence, 100th digit of d = 10th digit of 10d = 7 > 5. Hence, Sufficient. Statement 2. d/10 = 0.abcdef 1000th digit of d/10 = c = 7. So, 100th digit of d = 1000th digit of d/10 = 7>5. Hence, Suffic...
- by masoom j negi
Fri Dec 21, 2018 8:45 pm- Forum: Data Sufficiency
- Topic: Is the hundredths digit of the decimal d greater than 5?
- Replies: 5
- Views: 4466
Statement 1. The distance between r and 0 is 3 times the distance between m and 0. r = 3m or -3m. Since we don’t know the distance of ‘m’ from 0, we can’t find the value of ‘r’. Hence, Insufficient. Statement 2. 12 is halfway between m and r. This gives, m + r = 2 x 12 = 24 (m, r) could ...
- by masoom j negi
Fri Dec 21, 2018 8:42 pm- Forum: Data Sufficiency
- Topic: If m and r are two numbers on a number line, what is the
- Replies: 4
- Views: 954
Statement 1. If x is rounded to nearest hundredth digit, then 10 – x = 8.56 i.e. x = 1.44 This is possible for (a , b) = (3, >5) and (4 , <5). Hence, Insufficient. Statement 2. If x is rounded to nearest thousandth digit, 10 – x= 8.564 i.e. x = 1.436 This is only possible when a = 3 and b = 5. H...
- by masoom j negi
Fri Dec 21, 2018 8:35 pm- Forum: Data Sufficiency
- Topic: 1.4ab5
- Replies: 6
- Views: 4974
answer
Each digit of G is halved to make H. So, H is half of G. So, G + H = 2H + H = 3H So, the sum should be divisible by 3. Thus, C and E can’t be the answer because they are not divisible by 3. Now consider 153 = 102 + 51 It can’t be the value because G should be a 2-digit no. 150 = 100 + 50 It also...
- by masoom j negi
Fri Dec 21, 2018 8:34 pm- Forum: Problem Solving
- Topic: Sum of two digit number G+H
- Replies: 7
- Views: 3255