Search found 6 matches
since I cannot see the options, I don't know the final response but here is a way to solve it: x^2 + B = Ax - B <=> x^2 - Ax + 2B = 0 <=> <=> x=[A +- sqrt(A^2 - 8B)]/2 therefore we have to analyse de root: if A^2 - 8B < 0 - No intersection if A^2 - 8B = 0 - One intersection if A^2 - 8B > 0 - two int...
- by 69aero69
Fri Oct 17, 2008 5:44 am- Forum: Data Sufficiency
- Topic: Line Intersection
- Replies: 5
- Views: 2195
- by 69aero69
Fri Oct 17, 2008 3:55 am- Forum: Data Sufficiency
- Topic: A Simple but confusing DS [ 8a(1/4)b = ? ]
- Replies: 14
- Views: 3918
1) B = 3/2 A
then,
8^A . (1/4)^(3/2 A) =
=8^A . [(1/64)^A]^(1/2)=
=8^A . [(1/8)^2A]^(1/2)=
=8^A . (1/8)^A=
=1
therefore, Suf
2) we know nothing about B, therefore Insuf
Hence, the answer is A
- by 69aero69
Fri Oct 17, 2008 3:54 am- Forum: Data Sufficiency
- Topic: A Simple but confusing DS [ 8a(1/4)b = ? ]
- Replies: 14
- Views: 3918
- by 69aero69
Fri Oct 17, 2008 3:09 am- Forum: Problem Solving
- Topic: GMATPrep Q - eq. triangle inscribed in a circle
- Replies: 9
- Views: 3788
The correct anwser is 12Pi. Regarding the formula R=2/3 x H first, we know that H=sqrt(3)/2 x L second, consider the triangle of the attached drawing (two blue dots and the center of the circle) tan(30º)=Z / (L/2) <=> Z= sqrt(3) / 6 x L but L= 2 x H /sqrt(3) than, Z=1/3 x H Also, H = 1/3 x H + R the...
- by 69aero69
Thu Oct 16, 2008 10:18 am- Forum: Problem Solving
- Topic: equilateral triangle pS
- Replies: 61
- Views: 34576
The correct answer is (E). First, the sum of the internal angles of a quadrilateral is always 360º (can be decomposed in 2 triangles of 180º each) A) is insufficient we can have: A=90 B=90 C=60 D=120 or A=90 B=90 C=90 D=90 B) is insufficient we can have A=135 B=45 C=90 D=90 or A=100 B=60 C=120 D=80 ...
- by 69aero69
Thu Oct 16, 2008 8:05 am- Forum: Problem Solving
- Topic: Geomatry - am I missing something
- Replies: 6
- Views: 1734