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For a+b to be even, either both a and b must be even or both a and b must be odd. Since we will be choosing 5 possible "a" numbers and 5 possible "b" numbers, the total number of possibilities will be 25. The question is: How many of those will fit the above criteria? We have 3 w...

by elias.latour.apex

Sat Jan 13, 2018 6:06 am
Forum: Problem Solving
Topic: If a is to be chosen at random from the integers...
Replies: 2
Views: 815

If f(11) = 0 then one of the two terms inside (x-p) or (x-q) must be 0. So let's arbitrarily assign p=11.
Similarly if f(20) = 0 then we can assign q=20.

So what's f(10)? It will be (10-11) (10-20) = (-1) (-10) = 10

by elias.latour.apex

Fri Jan 12, 2018 5:35 am
Forum: Problem Solving
Topic: Let f(x)= (x-p)(x-q). If f(11)=f(20)=0, then f(10)=?
Replies: 4
Views: 1054

Here's another solution that some may find easier. We have 6 empty seats and three couples. How many people can sit in the first seat? 6 people -- any of the people waiting to be seated. However, once that happens, the person sitting next to him or her must be the other half of the couple, so we hav...

by elias.latour.apex

Fri Jan 12, 2018 5:32 am
Forum: GMAT Math
Topic: Permutation
Replies: 4
Views: 3969

Well, first we must determine how many possible starting points there are for the A. Since there are 9 possibilities for x, and 6 possibilities for y, there are 54 starting points for the triangle. But don't think that (A) is the answer. That number is far too low. Once we have selected A, we can se...

by elias.latour.apex

Mon Jan 08, 2018 7:27 pm
Forum: Problem Solving
Topic: Right triangle ABC is to be drawn
Replies: 2
Views: 735

The process of elimination is pretty straightforward. Let's run down the list. A. In all moderately dim light in which people without the disorder can read large print, people with the disorder cannot read such print. It does not say that. In fact, it says that people with this disorder have normal ...

by elias.latour.apex

Mon Jan 08, 2018 5:14 am
Forum: Critical Reasoning
Topic: GMATPrep EP1: People with a certain eye disorder
Replies: 1
Views: 726

Well, there are two ways I can see to solve this problem. Both involve determining the maximum number of possibilities, and that is what I will start by doing. VERMONT has 7 letters, but we are forming 5-letter combinations. So for the first letter, we have 7 choices. For the second, we have 6 (as w...

by elias.latour.apex

Sun Jan 07, 2018 5:55 am
Forum: Problem Solving
Topic: What percent of 5 letter combinations
Replies: 1
Views: 625

Imagine that we have 6 marbles in our hand and 4 empty bowls. We select one of the marbles. Where can we place it? In any of the 4 bowls. So we have 4 choices. Now we have the second marble in our hand. Where can we place it? Again, in any of the 4 bowls. So we have 4 more choices. The same goes for...


To make things easy, let us assume that our odd numbers are 1 and that our even numbers are 2. AB+C is even. So what if C is 1? Then AB must also be odd. In other words, all three numbers must be 1 (odd). What if C is 2? Then AB must also be even. So AB must equal 2 or 4. So these are our options: 1...

by elias.latour.apex

Sat Jan 06, 2018 10:35 am
Forum: Problem Solving
Topic: If A,B,C are three integers and AB+C is even . . . .
Replies: 3
Views: 727

The easiest solution is to assume that at the time both pumps started working on the basement, there were 12 units of water in the basement. This is the least common multiple of 4 and 3. Accordingly, the basement had 24 units of water in it when it was full. Since the pump X evacuated 12 units of wa...

by elias.latour.apex

Sat Jan 06, 2018 10:14 am
Forum: Problem Solving
Topic: Working at constant rate, pump X pumped out . . . . .
Replies: 1
Views: 2525

To have a zero at the end, a number must be multiplied by 10. Another way to think of this is that the number must be multiplied by the prime factors 5 and 2. 135 can be factored into 5 and 27. There are no other factors of 5 or 2. 42 can be factored into 2 and 21. There are no other factors of 5 or...

by elias.latour.apex

Sat Jan 06, 2018 10:02 am
Forum: Problem Solving
Topic: How many zeros does 135^19 x 42^17 end with?
Replies: 1
Views: 577

Critical reasoning questions are best handled by reading the question first. In this case, we find that the administrators like a certain criterion for eliminating workers. Our job is to show that this criterion is bad. Upon reading the text, we discover that the criterion is to eliminate those work...

by elias.latour.apex

Fri Jan 05, 2018 6:34 am
Forum: Critical Reasoning
Topic: Due to recent budget constraints
Replies: 1
Views: 563

Dispute

Meaning no disrespect to the Economist GMAT Tutor, but any of a number of answers is possible. It depends entirely on one's understanding of the question. The question states: "... the difference among the first 3 men was 2 [inches]...," a statement that EGT has taken to mean that man 1 is...

by elias.latour.apex

Fri Jan 05, 2018 5:54 am
Forum: Problem Solving
Topic: Sequence and Series
Replies: 2
Views: 860

This is an extremely controversial question drawn from the Manhattan GMAT CAT tests. Supposedly (A) is the best answer. The reasoning expressed by MGMAT instructors is that (A) offers an alternate explanation for the decrease in profit margins. Supposedly, increased competition is what is really cau...


The argument claims that many German computer users illegally copy software. Why? Because more computers are sold than commercial programs. Is this argument convincing? Not really. Perhaps many German computer users write their own programs, and thus do not need to buy commercial programs. This is a...

by elias.latour.apex

Tue Jan 02, 2018 6:10 am
Forum: Critical Reasoning
Topic: A recent survey found that more computers
Replies: 1
Views: 574

Statement 1 tells us that the number may be 111 or 111,111 or even 111,111,111. If you know the divisibility rules for 3, then you will know that each of these numbers is divisible by 3. To determine whether a number is divisible by 3, add up the unit digits. If the result is divisible by 3, then th...