Search found 31 matches
Let's try an experiment... I will give point out the conclusion and the reasoning and then see if that helps point people to the correct answer! We have a strengthen question. It is a normal type of question with a conclusion in the stimulus. That conclusion is that "the colleges in Tycho have...
- by chintudave
Thu Mar 24, 2011 9:28 pm- Forum: Critical Reasoning
- Topic: tycho city
- Replies: 10
- Views: 5413
Two faster ways to answer this problem without the mumbo jumbo! Common Realization for both the methods 1. From the problem it is clear that Ally and Betty have the same speed. So in my mind, i would eliminate Betty from the equation. i.e. I would make the problem simpler by assuming that there are...
- by chintudave
Sat Mar 06, 2010 11:19 pm- Forum: Problem Solving
- Topic: Time consuming rate problem
- Replies: 14
- Views: 2245
IMO E
Fewer is Countable and Lower is not. Therefore choices are B or E.
The hyphen between the "movies" and "fewer" in B breaks the sentence in correctly to make "-eater of the movies-".
Hence E.
- by chintudave
Tue Feb 16, 2010 9:23 pm- Forum: Sentence Correction
- Topic: GMAT Prep
- Replies: 10
- Views: 1842
Stupid Question!
Shouldn't "comparisons between products can be made at several stores" be "comparisons among products can be made at several stores" ?
What is being compared in this statement ?
- by chintudave
Tue Feb 16, 2010 9:04 pm- Forum: Sentence Correction
- Topic: What's wrong with the verbal statement
- Replies: 6
- Views: 1298
- by chintudave
Sat Feb 13, 2010 11:44 pm- Forum: Critical Reasoning
- Topic: must be true
- Replies: 11
- Views: 2623
[quote="Ian Stewart"][quote="harsh.champ"]If the integers m and n are chosen at random from integers from integers 1 to 100 with replacement, then the probability that a no. of the form 7m + 7n is divisible by 5 equals? (1)1/2 (2)1/4 (3)1/8 (4)1/16 (5)None of these ______________...
- by chintudave
Fri Feb 05, 2010 11:50 pm- Forum: Problem Solving
- Topic: Probability+Power+Divisibility rules
- Replies: 6
- Views: 2972
I thought the question was self sufficient. Stuart, am i overseeing something ? Based on what i interpret.... 5 Boys have 6 empty spots around them.... _B_B_B_B_B_ Let the girls pick four of the empty sport.... i.e. 6P4 = 360 The 5 boys can be adjusted in 5! ways So total combinations = 5! * 360 = 1...
- by chintudave
Fri Feb 05, 2010 11:07 pm- Forum: Problem Solving
- Topic: Permutation/Combination questions...
- Replies: 25
- Views: 15183
- by chintudave
Sun Jan 31, 2010 9:57 pm- Forum: Reading Comprehension
- Topic: Arbitration-judicial and political
- Replies: 3
- Views: 2692
With all the ambiguities out of the way. This is my painful way. Experts please share some quicker way! Since no two girls can sit together there are 30 unique options as listed below. 1-3-5-7 1-3-5-8 1-3-5-9 1-3-5-10 1-3-6-8 1-3-6-9 1-3-6-10 1-3-7-9 1-3-7-10 1-3-8-10 1-4-6-8 1-4-6-9 1-4-6-10 1-4-7-...
- by chintudave
Fri Jan 29, 2010 6:25 pm- Forum: Problem Solving
- Topic: Seating - Probability Question
- Replies: 13
- Views: 14115
Answer is C. Explanation: a. The given matrix is 9 dots on x axis and 6 dots on y axis. b. Choose 1 dot on y axis to plot the base of the triangle. 6C1 i.e 6 c. Choose 2 dots on x axis to plot the base on the y axis chosen in step b above. 9C2 i.e. 36 d. Now select 1 dot on y axis to plot the third ...
- by chintudave
Tue Jan 26, 2010 11:53 pm- Forum: Problem Solving
- Topic: coordinate geometry + combination
- Replies: 5
- Views: 1850
[quote="armaan700+"]The median value of a set of 9 positive integers is 6. If the only mode in the distrubution is 25 what is the least possible mean of the distribution.[/quote] Based on the data the set could be a. 1,2,3,4,6,7,8,9,25 b. 1,3,4,5,6,11,15,18,25 c. 1,2,4,5,6,25,25,25,25 . . ...
- by chintudave
Tue Jan 26, 2010 8:55 pm- Forum: Problem Solving
- Topic: mean
- Replies: 3
- Views: 1287
- by chintudave
Tue Feb 24, 2009 9:09 pm- Forum: Problem Solving
- Topic: 200 and 300 (both inclusive)
- Replies: 16
- Views: 24569
Re: 200 and 300 (both inclusive)
[quote="marcusking"]divisble by 2 = 1+100/2 =51 divisble by 3 =1+99/3 = 34 divisble by 5 = 1+100/5 = 21 divisble by 6 (both 2 and 3)= 1+94/6 =16 divisble by 15 (both 3 and 5)= 1+90/15 =7 divisble by 10 (both 2 and 5)= 1+100/10 =11 divisble by 30 (both 2,3 and 5)= 1+90/30 =4 Nos. divisble b...
- by chintudave
Tue Feb 24, 2009 7:36 pm- Forum: Problem Solving
- Topic: 200 and 300 (both inclusive)
- Replies: 16
- Views: 24569
- by chintudave
Sun Feb 22, 2009 2:15 pm- Forum: Problem Solving
- Topic: Addition Question
- Replies: 6
- Views: 1563
- by chintudave
Fri Feb 20, 2009 10:44 pm- Forum: Problem Solving
- Topic: permute with perfection
- Replies: 13
- Views: 3142