Search found 10 matches
If no condition applied, Total ways= 5!= 120 After condition Lets calculate the ways in which same neighbour can occur Lets fix one person, he can be srrounded by 2 ppl and rest 2 can be arranged in 2! way probability of choosing left n right side person = 4*3 Total possible ways= 2!*4*3=24 So, numb...
- by lalitaroral
Sat Dec 02, 2006 3:32 am- Forum: Problem Solving
- Topic: Difficult Math Problem #69 - Permutations
- Replies: 9
- Views: 5956
- by lalitaroral
Fri Dec 01, 2006 10:21 pm- Forum: Problem Solving
- Topic: Difficult Math Question #66 - Combinations
- Replies: 7
- Views: 4748
Patterns for structuring
Will be thankful if you can enlist some patterns for SC structure.
pls also tell more abt sentence division strategy
- by lalitaroral
Wed Nov 29, 2006 11:30 pm- Forum: Sentence Correction
- Topic: Sentence Correction Overview
- Replies: 12
- Views: 8788
Answer
Total letter count = 8 (COMPUTER) No of vowels = 3 Available positions for vowels = 4 No of free positions after vowel arrangement = 4-3 = 1 No of consonants= 5 Available positions for consonants= 5 (Inclusive vowel positions) Lets say positions are=>1 2 3 4 5 6 7 8 3rd place is already fixed for M,...
- by lalitaroral
Wed Nov 29, 2006 11:21 pm- Forum: Problem Solving
- Topic: Difficult Math Question #66 - Combinations
- Replies: 7
- Views: 4748
Answer
D:Defect, C:Correct
Possible combinations to select 4 TV(condition atleast 2 should be defective)
1. 3D 1C
2. 2D 2C
Case 1: 7C1*3D3
Case 2: 7C2*3D2
Total Possible ways: 7C1*3D3 + 7C2*3D2 = 84 Ways
- by lalitaroral
Wed Nov 29, 2006 10:22 pm- Forum: Problem Solving
- Topic: Difficult Math Question #67 - Combinations
- Replies: 5
- Views: 4356
Answer
C Explanation Total Contestants = 6 Condition Contestants= 5 Reason==>No Hope always finishes before Goldenrod, Consider both as one person as their order is N G, means they will b together all the times So, the possible arrangement for 6 people in which No Hope always finishes before Goldenrod = 5!...
- by lalitaroral
Tue Nov 28, 2006 8:17 am- Forum: Problem Solving
- Topic: Difficult Math Problems #65 - Permutations
- Replies: 8
- Views: 2707
- by lalitaroral
Tue Nov 28, 2006 8:06 am- Forum: Problem Solving
- Topic: Difficult Math Problem #64 - Combinations
- Replies: 5
- Views: 2144
- by lalitaroral
Sun Nov 26, 2006 8:47 pm- Forum: Problem Solving
- Topic: Difficult Math Problem #63 - Combinations
- Replies: 12
- Views: 3669
Sorry for typing mistake
possible combination=> 1. 2m 4w 2. 3m 3w Case 1: Probabilty of choosing 2m out of 8m = 8C2 Probabilty of choosing 4w out of 5w = 5C4 Total Probability = 8C2*5C4 If the selected two men are the one who doesnt want to be together, Probability of the two men coming together = 2C2 (1 possiblity) Actual ...
- by lalitaroral
Sun Nov 26, 2006 3:35 am- Forum: Problem Solving
- Topic: Difficult Math Problem #63 - Combinations
- Replies: 12
- Views: 3669
- by lalitaroral
Sat Nov 25, 2006 5:18 am- Forum: Problem Solving
- Topic: Difficult Math Problem #63 - Combinations
- Replies: 12
- Views: 3669