Search found 154 matches
Two stores
Two stores usually charge the same regular price for identical jars of peanut butter. This week, Store A is offering the jars of peanut butter for 10% less than regular price, and Store B is offering 6 jars of peanut butter for the regular price of 5. If 6 jars of peanut butter cost a total of $1.18...
- by talaangoshtari
Tue Aug 16, 2016 11:06 pm- Forum: Problem Solving
- Topic: Two stores
- Replies: 5
- Views: 1678
A list of consecutive integers
R is a list of 15 consecutive integers,and T is a list of 21 consecutive integers. The median of the integers in list R is equal to the least integer in list T. If the two lists are combined into one list of 36 integers, how many different integers are on the combined list? A. 25 B. 27 C. 28 D. 32 E...
- by talaangoshtari
Sat Aug 06, 2016 9:47 am- Forum: Problem Solving
- Topic: A list of consecutive integers
- Replies: 2
- Views: 4574
How Many Integers
How many integers between 1 and 300, inclusive, can be expressed as x^y, where x and y are integers greater than 1?
A.17
B.23
C.24
D.30
E.31
- by talaangoshtari
Sun May 01, 2016 1:43 am- Forum: Problem Solving
- Topic: How Many Integers
- Replies: 1
- Views: 3214
Hi.
I know that. But, this is a GRE question. In GRE we have some questions without the answer choices.
- by talaangoshtari
Mon Apr 04, 2016 11:01 am- Forum: GMAT Math
- Topic: Work Problem
- Replies: 6
- Views: 2886
Work Problem
The constant rate at which machines A works is 3/4 of the constant rate at which machine B works. Under normal conditions, machine A would complete x lots in 2 days. However, when a technician attempts to use machines A and B simultaneously, there is not enough electrical power to run both machines ...
- by talaangoshtari
Mon Apr 04, 2016 4:13 am- Forum: GMAT Math
- Topic: Work Problem
- Replies: 6
- Views: 2886
Geometry
What is the volume of the largest cube that can fit entirely within a cylinder with a volume of 45Ï€ and a height of 5?
A. 27
B. 54√2
C. 125
D. 216√2
E. 432√2
- by talaangoshtari
Sat Mar 12, 2016 11:17 am- Forum: Problem Solving
- Topic: Geometry
- Replies: 1
- Views: 1224
Yes, I know... But the problem is that this set is not evenly spaced. Therefore we cannot say that the mean is equal to the median.
1243 - 1234 = 9
1324 - 1243 = 81
1342 - 1324 = 18
1423 - 1324 = 99
1432 - 1423 = 9
Why do you consider this set the set of consecutive numbers?
- by talaangoshtari
Fri Jan 29, 2016 3:14 am- Forum: Problem Solving
- Topic: We make 4 digit codes and each digit of the code form from 1
- Replies: 9
- Views: 2472
One more way - Average of set = median of set = (1234+4321)/2 = 5555/2 Possible number of ways in which these 4 numbers can be arranged = 4*3*2*1 = 24 So sum of all of these numbers = average of the set multiplied by number of way of arrangement = 5555/2 * 24 = 66,660 Hi sitar, How did you find the...
- by talaangoshtari
Thu Jan 28, 2016 9:15 pm- Forum: Problem Solving
- Topic: We make 4 digit codes and each digit of the code form from 1
- Replies: 9
- Views: 2472
- by talaangoshtari
Thu Jan 28, 2016 8:09 pm- Forum: Problem Solving
- Topic: If each of 3 digit code form integers from 1 to 20, inclusiv
- Replies: 3
- Views: 1588
- by talaangoshtari
Tue Nov 10, 2015 11:40 pm- Forum: Problem Solving
- Topic: Mixture
- Replies: 7
- Views: 1927
- by talaangoshtari
Mon Nov 09, 2015 5:45 pm- Forum: Problem Solving
- Topic: Mixture
- Replies: 7
- Views: 1927
- by talaangoshtari
Mon Nov 09, 2015 10:01 am- Forum: Problem Solving
- Topic: Mixture
- Replies: 7
- Views: 1927
Hi GMATGuruNY,
How can we solve this problem by using alligation method?
I solved it but I couldn't find the answer:
40-----------25-----------0, so, V:O is 5:3.
- by talaangoshtari
Mon Nov 09, 2015 4:28 am- Forum: Problem Solving
- Topic: Mixture
- Replies: 7
- Views: 1927
- by talaangoshtari
Sun Nov 08, 2015 8:20 pm- Forum: Problem Solving
- Topic: Mixture
- Replies: 7
- Views: 1927
Hi parthdpatel, Multiply the first equation by 5 and the second equation by 4, (5)[4t1 + 5t2 = 35] => 20t1 + 25t2 = 175 (4)[5t1 + 4t2 = 37] => 20t1 + 16t2 = 148 Now we can subtract the two equations: 25t2 - 16t2 = 175 - 148 = 27 => 9t2 = 27, So t2 = 3, and 20t1 + 25(3) = 175 => t1 = 5
- by talaangoshtari
Sun Oct 18, 2015 7:37 pm- Forum: Problem Solving
- Topic: Time And Distance Problem
- Replies: 9
- Views: 7001