Search found 27 matches
I would suggest that you contact those who run the tests (Pearson VUE, I believe) and find out. They should have customer service numbers that you can call, and this information should be on your confirmation email when you first scheduled your test. (I must say that this is a very unique situation ...
- by madeline
Mon Jan 12, 2009 8:51 pm- Forum: GMAT Strategy
- Topic: URGENT - rescheduling test date - help please!!!
- Replies: 3
- Views: 1351
Basic things derived from what's given: OC = OB (=> OBC = BCO) AB = OC => AB = OB => BAO = BOA (1) COD = 60 => BAO + BCO = 60 => BAO + OBC = 60 Because BAO + BOA = OBC (basic property of triangle) And recall that BAO = BOA => 2BAO = OBC => BAO + 2BAO = 60 => 3BAO = 60 => BAO = 20 (2) BCO = 40 => OBC...
- by madeline
Sun Nov 16, 2008 1:18 pm- Forum: Data Sufficiency
- Topic: GMAT Prep Geometry
- Replies: 2
- Views: 1394
Woah... whatever you do, DON'T guess the last 7! The scoring algorithm is approximately such that for every question you get right, it gives you a harder question. If you get that right, it gives you an even harder question, etc. If you get one wrong, it gives you an easier question. And so on. The ...
- by madeline
Sat Nov 15, 2008 11:11 pm- Forum: GMAT Math
- Topic: Math section - timing & wrong answer distribution questi
- Replies: 2
- Views: 1871
Try Manhattan GMAT's practice exams. I found the questions to be very tough, especially given the time constraints. Even if you don't time yourself, they're still quite tough. Quite unnecessarily tough, IMHO. Their scoring algorithm truly gives you a tougher question for each tough question you answ...
- by madeline
Sat Nov 15, 2008 10:52 pm- Forum: GMAT Math
- Topic: Tough Question
- Replies: 1
- Views: 1586
(1) Square root of A^2 - B^2 is NOT equal to A-B! In fact, it has nothing to do with A-B. As you do know yourself, (A-B)(A-B) = A^2 - 2AB + B^2, not simply A^2 - B^2 (2) A^2 - 2AB + B^2 =1 From this we can deduce either of the following: (A-B)(A-B) = 1 or (B-A)(B-A) = 1 If the former is true, then A...
- by madeline
Sun Oct 19, 2008 8:26 pm- Forum: Data Sufficiency
- Topic: Kaplan DS
- Replies: 6
- Views: 1525
Rephrasing the question: PRS - PQR = ? (1) QPR = 30 QPR + PQR = PRS This is a basic property of triangles. If you didn't know it, think of it this way: PRQ + QPR + PQR = 180 PRQ + PRS = 180 Therefore, QPR + PQR = PRS Anyway, so 30 + PQR = PRS PRS - PQR = 30 Statement 1 alone is sufficient. (2) PQR +...
- by madeline
Sun Oct 19, 2008 8:07 pm- Forum: Problem Solving
- Topic: triangle PQR
- Replies: 1
- Views: 1105
Obviously you figured out that neither statement alone is sufficient, so let's look at the 2 statements together. Notice that the number of children has to be a multiple of 10. Its ratio to number of women is 2 to 5, and its ratio to number of men is 5 to 11. This means that it needs to be evenly di...
- by madeline
Sun Oct 19, 2008 7:28 pm- Forum: Problem Solving
- Topic: KLMN rectangles ratios
- Replies: 3
- Views: 1464
Let's only look at statement 2. The dishwasher has 55 minutes remaining in its cycle. Statement 2 says: Putting away the dishes will take Patrick 7 minutes. Patrick needs to put away the dishes after the dishwasher completes its cycle. So completing the cycle and putting away the dishes will take 62...
- by madeline
Mon Oct 13, 2008 9:04 pm- Forum: Data Sufficiency
- Topic: Word Prob - Logical question
- Replies: 2
- Views: 1240
I would say the answer is C. Of course this is not "official", but I'm pretty sure I'm correct. If you order all the projects by number of employees assigned, the "median" means you want to know the number of employees assigned for the project at the 50th percentile. Makes sense?...
- by madeline
Mon Oct 13, 2008 8:50 pm- Forum: Problem Solving
- Topic: please help ...OA needed urgently
- Replies: 1
- Views: 1477
My #23 in OG 11 goes like this:
If the positive integer x is a multiple of 4 and the positive integer y is a multiple of 6, then xy must be a multiple of which of the following?
I. 8
II. 12
III. 18
- by madeline
Mon Oct 13, 2008 8:32 pm- Forum: Problem Solving
- Topic: Error in OG 11?
- Replies: 4
- Views: 1828
(1/5)^n > (1/5)^-2 = N>-2 This step in (2) is wrong. If (1/5)^n > (1/5)^m, then n<m. This is true for all numbers between 0 and 1 (such as 1/5). Consider the following: (1/5)^-3 = 5^3 = 125 (1/5)^-2 = 5^2 = 25 ... (1/5)^2 = 1/25 (1/5)^3 = 1/125 So the greater the power, the smaller your result. Hen...
- by madeline
Tue Oct 07, 2008 5:32 pm- Forum: Problem Solving
- Topic: negative exponents
- Replies: 1
- Views: 1377
Yes, these ones are certainly harder than the earlier ones. GMAC mentions somewhere that the questions in their books are ordered by level of difficulty, so the later the questions are in a section, the more difficult they become.
- by madeline
Fri Sep 19, 2008 5:16 pm- Forum: Problem Solving
- Topic: Last Exercises OG Ed.11
- Replies: 1
- Views: 1264
I assume you meant >= when you typed <= the two times. If you took GMATPrep more than FIVE times, those final scores are going to be very skewed since you would encounter more and more familiar problems. I recommend the Manhattan GMAT series of books for brushing up on the basics tested (minus the r...
- by madeline
Thu Aug 28, 2008 5:10 pm- Forum: I just Beat The GMAT!
- Topic: Highly desponded by the GMAT scores.
- Replies: 10
- Views: 4009
ritula, Stuart and warlock offer some nice explanation for if B wasn't totally inside of A, and warlock's Venn diagram (and formula) is the way to go! This would work for ANY problem with 3 sets intersecting. I usually like to find shortcuts, such as ignoring B in this problem, which made my calcula...
- by madeline
Wed Aug 20, 2008 8:18 am- Forum: Problem Solving
- Topic: a set problem...
- Replies: 9
- Views: 1873
Now I really need a whiteboard. I will attempt to explain this without one and see how it goes! Draw a rectangle on your paper. This is your sample space of 60 people. Draw a circle inside, label it A. This circle represents 48 people. Draw a circle inside of A, label it B. This represents those who...
- by madeline
Tue Aug 19, 2008 8:25 pm- Forum: Problem Solving
- Topic: a set problem...
- Replies: 9
- Views: 1873