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Probability of getting 0 blue disks p(0) = 3/4 * 3/4 * 3/4 * 3/4 = 81/256
Probability of getting 4 blue disks p(4) = 1/4 * 1/4 * 1/4 * 1/4 = 1/256
Probability of getting 1,2, or 3 blue disks p(1, 2, 3) = 1 - 81/256 - 1/256 = 174/256 = 87/128 (C).
- by beingNeha
Sat Jul 06, 2013 10:23 pm- Forum: Problem Solving
- Topic: Probability Disks
- Replies: 6
- Views: 4450