Fairly surprised why no one answered this question..Here's my take on it.. We can either pick numbers or go for reducing the options. I chose reduction.. II is the easiest to evaluate..lets go with that. a#0 = a+0 - a*0 = a - 0 = a. So II is true. Eliminate all except c and e. So, we need to evaluat...

so 6 is a probable answer.. What if x=-4?

The average would then be 4: (-4+2+4+8+10)/5 = 4; The median too would be +4. So we have two different answers. Wat say?

Choice B leads us to believe that the clauses (education being in the university, students being offered a broad range of courses) are on equitable terms, whereas, actually, the second part is a subset of the first part...Let me reword the sentence a bit to fit the choice B - Edith was convinced tha...

umm..how about this? we have 1. sqrt[(x+4)(x-5)] < 11 => as kevin pointed out, 0 < (x+4)(x-5) < 121 2. sqrt[(x+4)(x-5)] > 10 => (x+4)(x-5) > 100 Cant figure out the value of x from any individual statement..combining the two, 121 > (x+4)(x-5) > 100 expanding, 121 > x^2 - 5x + 4x -20 > 100 adding 20 ...

Did get the same result, though used a different method..can someone verify? I) Calculate height of the triangle - dropping an altitude to the base, the right triangle would be in the ratio of 1:sqrt(3):2. Since we have an equilateral triangle, the median from A would create a right triangle with on...

Yup..
Right about here..
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Hmm..Fibo, you have considered the set p to be [1,2,3,4,5]. If you look at stmt 1, it says 'For any int in P, sum of 3 and that int is also in P". Let us take the set you have considered - if 1 is present, 1 + 3 should also be present in P. 4 is. Now since 4 is present in P, 4 + 3 should also b...