Search found 23 matches
hi rupanator, i shouldn't say this but i have to. you are doing a mistake by reducing your target. it's nothing but you are accepting your defeat. never do that. when you scored above 650, you should try and get 700. try and achieve your goal, give it till the last minute, but never give up. I saw y...
- by nil4700
Mon Nov 17, 2008 8:08 pm- Forum: GMAT Strategy
- Topic: Retaking GMAT: Prep in 30 days
- Replies: 6
- Views: 1947
hi rupantor, From your post the only reason i can think of is you are tensed and putting too much pressure on yourself to score well. If you were able to score that well in the practice tests, you should have learned a lot and done well. you might have taken a lot of pressure while taking the test. ...
- by nil4700
Mon Nov 17, 2008 4:56 am- Forum: GMAT Strategy
- Topic: Retaking GMAT: Prep in 30 days
- Replies: 6
- Views: 1947
Taking the test second time
hello all,
I'm taking GMAT for the second time, after one year gap. My question is do i need to provide any extra details while registering for the test or during the test?
I'm not sure if this is the right way to ask such a question but I hope I will get an answer from you guys.
Thanks,
Anil
- by nil4700
Wed Nov 12, 2008 5:15 am- Forum: GMAT Strategy
- Topic: Taking the test second time
- Replies: 1
- Views: 1134
Target 700+
Hello all, I gave my GMAT last year October 15th and scored 540 (M48, V17). To be frank, I always knew that I'm not good in verbal and truly it turned out to be so. So, I took a long break and concentrated on my career, but never gave up another shot on GMAT. I have started this second stint to crac...
- by nil4700
Tue Nov 11, 2008 9:12 am- Forum: GMAT Strategy
- Topic: Target 700+
- Replies: 0
- Views: 1093
They need 8 places in all. - - - - - - - - First keep John in first place, that leaves Sussane 3 places to be seated. J G B G/S B G/S B G/S so there are 3 ways. Now, the boys can be seated in 3! ways and girls also in 3! ways. ==> 3*3!*3! But this arrangement is again possible if John is seated on t...
- by nil4700
Mon Sep 22, 2008 3:57 am- Forum: Problem Solving
- Topic: Susan & John ready to fight as ever(combinatorics)
- Replies: 7
- Views: 1963
Total numbers = 1000. numbers divisible by 11 = 90 (last multiple is 990). ==> 910 numbers left. nubers divisible by 5 are 200. => of these 200 numbrs divisible by 7 are 28 (28 * 7 = 196). So numbers divisible by 35 are 28. Numbrs left = 910 - 28 = 882. But, in those 28, we have 385 and 770 which ar...
- by nil4700
Mon Sep 22, 2008 3:36 am- Forum: Problem Solving
- Topic: Integers
- Replies: 5
- Views: 2216
Total numbers = 1000. numbers divisible by 11 = 90 (last multiple is 990). ==> 910 numbers left. nubers divisible by 5 are 200. => of these 200 numbrs divisible by 7 are 28 (28 * 7 = 196). So numbers divisible by 35 are 28. Numbrs left = 910 - 28 = 882. But, in those 28, we have 385 and 770 which ar...
- by nil4700
Mon Sep 22, 2008 3:35 am- Forum: Problem Solving
- Topic: Integers
- Replies: 5
- Views: 2216
For the second question: Since the median is 25, and the total numbers are odd, the middle number is 25. That means, there are 7 numbers on either side of number 25 in the set when they arranged in order. To maximize the highest number the numbers that are below 25 should be closer to 25 (so that in...
- by nil4700
Mon Sep 22, 2008 2:50 am- Forum: Problem Solving
- Topic: average
- Replies: 5
- Views: 6566
let the no of boys be B and the no of girl be G. B+G = 21. 2/3 * B + 1/3 * G should be maximum. that means B and G should be multiples of 3. possibilities are (B,G)==>: (3,18), (6,15), (9,12),(12,9),(15,6), (18,3). For the sum 2/3*B+1/3 *G to be maximum B should have the highest value possible which...
- by nil4700
Mon Sep 15, 2008 11:00 pm- Forum: Problem Solving
- Topic: Arco question
- Replies: 5
- Views: 1656
Hello all, there are 10 numbers that satisfy the condition: 101, 102, 103, 104.... 109. the sentence only says "first digit and the last digit of the integer are each equal to one more than the middle digit". It is not saying that the FIRST digit and the THIRD digit must be same. So, proba...
- by nil4700
Mon Sep 15, 2008 3:46 am- Forum: Problem Solving
- Topic: Digit problem
- Replies: 7
- Views: 5415
Hello all, there are 10 numbers that satisfy the condition: 101, 102, 103, 104.... 109. the sentence only says "first digit and the last digit of the integer are each equal to one more than the middle digit". It is not saying that the FIRST digit and the THIRD digit must be same. So, proba...
- by nil4700
Mon Sep 15, 2008 3:44 am- Forum: Problem Solving
- Topic: Digit problem
- Replies: 7
- Views: 5415
As per the rules, a pronoun refers to the noun closer to it. Can't we take this for granted and say THEIR or THEM in the first three options are also in contention. If not are we just eliminating them for the sake the BEST answer?
- by nil4700
Mon Jul 07, 2008 5:29 am- Forum: Sentence Correction
- Topic: As researchers continue to probe the highly expressive
- Replies: 5
- Views: 5909
@jan08:
Can you please explain why you have eliminated option "E"? As per your post IT is being refered to the SUBMARINES, in fact it is actually refering to the SHIP, similar to the word "IT" in option "C". Can you explain this?
- by nil4700
Wed Jul 02, 2008 5:20 am- Forum: Sentence Correction
- Topic: 1000 SC 169
- Replies: 11
- Views: 6050
@jan08:
Can you please explain why you have eliminated option "E"? As per your post IT is being refered to the SUBMARINES, in fact it is actually refering to the SHIP, similar to the word "IT" in option "C". Can you explain this?
- by nil4700
Wed Jul 02, 2008 5:20 am- Forum: Sentence Correction
- Topic: 1000 SC 169
- Replies: 11
- Views: 6050
@jan08:
Can you please explain why you have eliminated option "E"? As per your post IT is being refered to the SUBMARINES, in fact it is actually refering to the SHIP, similar to the word "IT" in option "C". Can you explain this?
- by nil4700
Wed Jul 02, 2008 5:19 am- Forum: Sentence Correction
- Topic: 1000 SC 169
- Replies: 11
- Views: 6050