He is trying to find the y-intercept of the line, which is the y-coordinate of the point where the line intersects the y-axis (in other words, the y-coordinate of the point where x=0). He moves six units to the right from the point (-6,-1) because moving 6 units to the right in the horizontal direct...

I agree with B for this one. Statement (1) gives us that a^2+b^2 is an integer, but that may or may not mean that the sqrt is an integer. However, Statement (2) tells us that a^2 = 3(b^2). Then we can substitute this into the original equation sqrt(a^2+b^2) = sqrt(3(b^2)+(b^2)) = sqrt(4(b^2)) = 2b S...

The answer is not A because just knowing the information in statement 1 (that s-r = 5) is not enough to determine how many integers exist with r<n<s. There could be four OR five integers that satisfy this and we cannot know which is the correct answer. For example, let r and s be 2 and 7. Then on th...

I agree with D for this one. The average of an odd number of consecutive integers will just be the middle number in the list. (for example, average of 5, 6, 7 = 6). So in a list of 11 consecutive integers, the 6th number in the list will be the average. Similarly, in a list of 9 consecutive integers...

I think this one is B - Statement (2) alone is sufficient. Statement (1) tells us that one of the homes was purchased for $110,000. We know that the sum of the 3 purchase prices must be $360,000 (for avg to be 120K), so the other 2 homes must have prices that sum to $250,000. However, there is no wa...

I think this one is A. Let x be the fraction of the ice cube above the water. We are told that 1/7 < x < 1/6 Then for the lower bound of this range, the ratio of the mass above the water to the mass below is (1/7)/(6/7) (1/7 above compared to 6/7 below) =(1/7)*(7/6) = 1/6. And, for the upper bound o...

I would use the formula (a^2)+(b^2) = (c^2) (pythagorean theorem), where a and b are the legs of a right triangle and c is the hypotense. If you draw a right triangle by connecting 2 corners of the square, you will note that the hypotenuse of the right triangle you create is also the diameter of the...

I went about this one by first finding the number of different groups possible without any restrictions and then finding the number that involved a married couple and subtracting. Number of possible groups 8 people, choose 3 = (8!)/(3!5!) = 56 (from formula for combinations) Number of possible group...