Search found 131 matches
What is the source?
It does not look like a real GMAT question, moreover options are really close.
Thanks
Puneet
- by puneetkhurana2000
Tue Dec 25, 2012 4:45 pm- Forum: Problem Solving
- Topic: Interest question
- Replies: 4
- Views: 1464
Let the original investment is x....(1) During purchase we get 10% return which equals 0.1*x....(2) Compound Interest starts from second year (and a compounding 5% for each year after the first) , so Compound Interest from start of second year to the end of second year equals (x(1+5/100) - x)....(3)...
- by puneetkhurana2000
Tue Dec 25, 2012 4:34 pm- Forum: Problem Solving
- Topic: Interest question
- Replies: 4
- Views: 1464
puneetkhurana2000 wrote: Statement 1) 2R is evenly divisible by 3, so 2R can be 3,6,9,12,15...so acceptable values of R are 3,6,9... Hey Puneet, Taz wrote: As per your explanation, if Quote: 2R can be 3,6,9,12,15... ... so according to that, the first acceptable value of R would be 3/2 right (for 2...
- by puneetkhurana2000
Tue Dec 25, 2012 6:23 am- Forum: Data Sufficiency
- Topic: Divisibility DS
- Replies: 4
- Views: 1240
puneetkhurana2000 wrote: Take the case as 1-2(one sibling each) and 3-4(one sibling each) and 5-6-7(two siblings each) ..so 1-2-3-4 have one sibling each and 5-6-7 have two siblings each. Total ways 7C2 = 21 Favorable ways 2C1*2C1 + 3C1*2C1 + 3C1*2C1 = 16 Answer is 16/21 ritind wrote: Can u explain...
- by puneetkhurana2000
Tue Dec 25, 2012 6:19 am- Forum: Problem Solving
- Topic: In a room filled with 7 people, 4 people have exactly 1
- Replies: 7
- Views: 6020
- by puneetkhurana2000
Tue Dec 25, 2012 6:13 am- Forum: Data Sufficiency
- Topic: Probability: Tough Nut
- Replies: 5
- Views: 1456
If there are more than 20 students, P(two students picking up the same integer) is 100%.
Statement 1) 1 <= Number of Students < 30, Not Sufficient!!!
Statement 2) Number of Students = 30, this is more than 20 so Sufficient!!!
Answer B.
- by puneetkhurana2000
Tue Dec 25, 2012 6:08 am- Forum: Data Sufficiency
- Topic: Probability: Tough Nut
- Replies: 5
- Views: 1456
There's one more way we know the terms are in AP sum of terms = [no of terms(first term + last term)]/2 first term = 1/201 last term = 1/300 no of terms = 100 Put the values in formula sum of terms = 0.41 option A 0.33<0.41<0.5 OA is A The terms are not in AP, the question is about reciprocals. 1/2...
- by puneetkhurana2000
Mon Dec 24, 2012 11:12 pm- Forum: Problem Solving
- Topic: Arithmetic Estimation (sum of consecutive intergers)
- Replies: 6
- Views: 2322
Statement 1) 2R is evenly divisible by 3, so 2R can be 3,6,9,12,15...so acceptable values of R are 3,6,9... and all these are evenly divisible by 3. Sufficient!!! Statement 2) 3R is evenly divisible by 3, so 3R can be 3,6,9,12,15...so acceptable values of R are 1,2,3,4,5... and some of these(3,6..) ...
- by puneetkhurana2000
Mon Dec 24, 2012 10:27 pm- Forum: Data Sufficiency
- Topic: Divisibility DS
- Replies: 4
- Views: 1240
Alternately we can solve this by:- A) 0.456 B) 1/2 - (1/2)^4 = 7/16 = 40% of 16(6.4) + less than 5% of 16(0.8) = < 0.45(approx) C) 300/650 = 6/13 = 40% of 13(5.2) + little more than 6% of 13(0.78) = > 0.46(approx) D) 3*(3/19) = 9/19 = 40% of 19(7.6) + little more than 7% of 19(1.33) = > 0.47(approx)...
- by puneetkhurana2000
Mon Dec 24, 2012 9:05 pm- Forum: Problem Solving
- Topic: arithmetic problem
- Replies: 8
- Views: 2592
LCM will be tedious I believe so approximation can work. A) 0.456 B) 1/2 - (1/2)^4 = 7/16 = 7 * 6% = .42(approx) C) 300/650 = 6/13 = 6 * 7% = .42(approx) D) 3*(3/19) = 9/19 = 9 * 5% = .45(approx) E) sqrt(0.17) -- closer to 0.4 So, now its down to A or D. From here its better to actually calculate th...
- by puneetkhurana2000
Mon Dec 24, 2012 8:35 pm- Forum: Problem Solving
- Topic: arithmetic problem
- Replies: 8
- Views: 2592
First of all where were you man or Manpreet Ji. I always find your questions of high quality. We need to find P(rain or roar). And March has 31 days. Statement 1) last March, the lion never roared on a rainy day. I can safely assume that this statement is not sufficient as it does not give me any da...
- by puneetkhurana2000
Sun Dec 23, 2012 9:55 pm- Forum: Data Sufficiency
- Topic: probability question:
- Replies: 5
- Views: 1327
- by puneetkhurana2000
Sun Dec 23, 2012 4:09 pm- Forum: Problem Solving
- Topic: problem9
- Replies: 4
- Views: 2062
Assuming no match ends in a draw. WE can solve this using mixtures as:- Winning ratio in first twenty games is 17/20. Winning ratio overall is 3/4 , for simplification lets make this 3/4 equivalent to 15/20. Lets say Winning ratio in rest of ten games is x/10, for simplification lets make this x/10 ...
- by puneetkhurana2000
Sun Dec 23, 2012 4:06 pm- Forum: Problem Solving
- Topic: problem9
- Replies: 4
- Views: 2062
- by puneetkhurana2000
Sun Dec 23, 2012 3:47 pm- Forum: Data Sufficiency
- Topic: DS: Absolute Value again!
- Replies: 6
- Views: 1388
And Lets say if the question is:- What is the total number of integers between 100 and 200 that are divisible by both 3 and 4?
So we have to look for digits divisible by 12(LCM of 3 and 4) only.
This equals (192 - 108)/12 + 1 = 8.
Hope this helps!!!
- by puneetkhurana2000
Sun Dec 23, 2012 3:43 pm- Forum: Problem Solving
- Topic: PROBLEM8
- Replies: 6
- Views: 1353