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X intercept is the value of X such as Y = 0 For instance: -) Y = 4 X, Y = 0 when X = 0 -) Y = 4X + 2, Y = 0 when X = -1/2 Whith an equation of the form y = ax^2 + bx + c, you should compute E = b^2 - 4ac If E = b^2 - 4ac > 0, there are two intercepts given by (-b+sqrt(E))/2a and (-b-sqrt(E))/2a If E...

by Magellan

Thu May 15, 2008 1:59 am
Forum: Problem Solving
Topic: Help me about the concepts
Replies: 3
Views: 1315

When b^2 - 4ac > 0 --> 2 intercept When b^2 - 4 ac = 0 --> 1 intercept When b^2 - 4 ac <0> No intercept (1) a>0 This does not tell us anything because b^2 - 4ac can be either negative or positive E.g.: - If b=1, a = 1, C = 4, 1^2 - 4 x 1 x 4 = 1 - 16 = -15 - If b=5, a = 1, C = 4, 5^2 - 4 x 1 x 4 = 2...

by Magellan

Thu May 15, 2008 1:39 am
Forum: Problem Solving
Topic: Help me about the concepts
Replies: 3
Views: 1315

I don't think it is the answer.

IMO, this transition is not correct:
D^D = {(2^(2^5)}^ (2^32)
D^D = (2)^{(2^5)*(2^32)}


I think the answer is the following:
D^D
= 2^32^2^32
= 2^2^5^2^32
= 2^2^320

P = 2^320

by Magellan

Thu May 15, 2008 12:39 am
Forum: Problem Solving
Topic: Exponents of exponents
Replies: 3
Views: 1372

Total hours of television watched: 60 x 0.5 = 30 hours SO, when we evaluate the ratios, the need to be 'compatible' with a total of 30 hours. It means that we should be able to find integers N & R such as N x 2 + R x 1.5 = 30 1) 3 x 2 / 16 x 1.5 = 6/24 --> Compatible (N=3, R=16) 2) 1 x 2 / 2 x 1...

by Magellan

Thu May 15, 2008 12:23 am
Forum: Problem Solving
Topic: Ratio question
Replies: 2
Views: 1275

5 crates for a total weight of 5 x 250 = 1250 A) If known crates are heaviest within possible range 2 x 205 = 410 2 x 310 = 620 Total: 1030 5th crate: 1250 - 1030 = 220 B) If known crates are lightest within possible range 2 x 200 = 400 2 x 300 = 620 Total: 1000 5th crate: 1250 - 1000 = 250 --> Rang...

by Magellan

Thu May 15, 2008 12:15 am
Forum: Problem Solving
Topic: Arithmetic mean range
Replies: 1
Views: 1314

Area = basis * height

Basis= 5 sqrt(2)

Height: We can draw a line from B to the segment AD (perpendicalur to AD) --> this is the height. The triangle formed is a 45/45/90 triangle. Therefore, the height is 5.

Area = 5 sqrt(2) * 5 = 25 sqrt(2)

by Magellan

Thu May 15, 2008 12:04 am
Forum: Problem Solving
Topic: Geomatry Question
Replies: 1
Views: 1284

Yes, I will definitly take it again because I need at least 720-730 for the scholls where I will apply. I will however wait some time before taking it again (probably after the summer) when I will be 'fresh' again.

Thanks a lot for your advice

by Magellan

Wed May 14, 2008 10:43 pm
Forum: I just Beat The GMAT!
Topic: Beaten by GMAT: 670 (Q48, V34)
Replies: 12
Views: 5971

Exponents of exponents

How to solve a question like this one:

D = 2^32 and 2^P = D^D

What is the value of P?

Basically, you get to 2^P = 2^32^2^32 --> How to proceed?

by Magellan

Tue May 13, 2008 11:04 pm
Forum: Problem Solving
Topic: Exponents of exponents
Replies: 3
Views: 1372

Hello guys, Thanks for your replies. Here is a summary of my preparation. For my study strategy, I went through the following books: - Kaplan - Kaplan 800 (2x) - Manhattan SC (3x) - O.G. 10 My full list of score: 1- MGMAT 1 - 680 (Q47, V35) - 2 months before the test 2- MGMAT 2 - 640 (Q46, V32) - 1....

by Magellan

Tue May 13, 2008 10:31 pm
Forum: I just Beat The GMAT!
Topic: Beaten by GMAT: 670 (Q48, V34)
Replies: 12
Views: 5971

Beaten by GMAT: 670 (Q48, V34)

Hello all, I did the GMAT this morning and scored far below my target. I would have been satisfied by anything above 730. I am satisfied with my Q score but V is way below my averages. I am a bit confused right now about reasons of such a low score in Verbal. During the test, I felt questions were t...

by Magellan

Tue May 13, 2008 4:14 am
Forum: I just Beat The GMAT!
Topic: Beaten by GMAT: 670 (Q48, V34)
Replies: 12
Views: 5971

Please, disregard my post, it was wrong.

by Magellan

Mon May 12, 2008 9:00 am
Forum: Data Sufficiency
Topic: GMAT Prep?? (Coordinate Geometry)
Replies: 2
Views: 1630

Your total costs are wrong (you have to include the down payement as well).

Total A: 8 + 32 + 12.8 = 52.8
Total B: 10 + 40 + 16 = 66

--> diff is 13.2

by Magellan

Mon May 12, 2008 7:08 am
Forum: Problem Solving
Topic: GMAT Prep Cost ofo machines
Replies: 2
Views: 1485

We already KNOW that the sum is 8.

To get a sum of 8, we can have:
- 4/4
- 5/3
- 3/5
- 6/2
- 2/6

2 possibilities out of 5 have a '5'

--> I would go with (D)

by Magellan

Mon May 12, 2008 6:44 am
Forum: Problem Solving
Topic: Probability
Replies: 4
Views: 1584

that question is either incredibly poorly worded or the answer is wrong. the way it reads, we are looking for the sum of k1-k10, or k1+k2+k3...+k10 the first part of the equation (-1^k) should negate itself because k1=1. k2=-1, k3=1, k4=-1, and so on so that by k10 (or the sum to any even integer),...

by Magellan

Mon May 12, 2008 1:38 am
Forum: Problem Solving
Topic: GMAT Prep ?? (Kth term)
Replies: 22
Views: 11016