Hi Friends, I am back after some break. The question is from Princeton Bin 4- No 21. The question seem confusing at first, but after analysis, we can notice that the verb 'weights' goes with Cubby but not Brian and Andrea (More of a SC question than PS :lol: ). So, C=A+(p/4). I made the same mistake...

IC, Many thanks to u Madhavi.

I think that I need some more of these kind of questions to work on in order to re-master my high school Maths

Thanks

That's great, the OA = C.

But Y you keep dividing by 3 and 2 on the second and third day?

Just reduce all the prime numbers to the power of 10, then add the power only, we don't mind with the exact result.

i.e. 2*3*5*7*11*17*19 = 10*21*11*17*19

this is eaual to
1..0*2.1*1.1*1.7*1.9 * 10^6

= 9....*10^6

Ans = D

I don't know whether there is a proper mathematical way to solve this problem but I did it this way. I tabulate is as follows: see attachment from the table we can see that the total repeated Nos for 700 = 30 So for 800 and 900 inclusive = 30 *3 = 90 We should less repeated Nos (3*3 = 9) = 81 Rememb...

Ans is A=12.5

let X be the point on the x-axis for point R [which has coordinates(7,0)].

Calculate area of trapezoid OQRX = 49/2

Calculate area of triangles OQP=6 and PRX=6.

Area of PQR=49/2 - 12 = 25/2.

More detailed explanation.

From properties of triangle : r=2, and angle PO with horizontal = 30 deg.
Therefore angle QO with horizontal = 60 deg.

=> from properties of triangle once more s=1 and t=root(3).

That' it.