Search found 5 matches
IMO A All Historians are able to spot trends Anyone able to spot trends is able to distinguish the significant from insignificant Hence the conclusion should be: All historians are able to distinguish significant from insignificant All X are able to Y However the given conclusion is: Anyone who can ...
- by sanju438
Thu Aug 13, 2009 7:12 pm- Forum: Critical Reasoning
- Topic: Historians and trends
- Replies: 10
- Views: 2136
- by sanju438
Fri Jul 17, 2009 4:41 am- Forum: Lounge
- Topic: FREE Live Online GMAT Math Session
- Replies: 11
- Views: 4759
from (1) n - 3 = 2K . n = 2K + 3. So n can be 3, 5, 7, 9 etc insufficient (2) 2K-4 is divisible by 7. 2K can be 11, 18, 25, 32, 39 etc Since K is integer, K can be 9, 16, etc insufficient Combining (1) and (2) n - 3 = 2K => n -3 = 7M + 4 (where M is any integer since 2K - 4 is divisible by 7) This m...
- by sanju438
Thu Oct 02, 2008 1:33 pm- Forum: Data Sufficiency
- Topic: From OG Quantitative Review
- Replies: 4
- Views: 2514
S = n(n+1)/2
(1) S < 20. Insufficient. n can be 1, 2 etc
(2) S^2 > 220. Insufficient . n can be 6, 7, etc
Taking (1) and (2) together, only n = 5 is possible. Sufficient
- by sanju438
Wed Oct 01, 2008 1:07 pm- Forum: Data Sufficiency
- Topic: test 13 #20
- Replies: 4
- Views: 3252
Let x = 5, y = -8
Condition 1) z = x + y . Hence z = -3
(y-z) = -5. clearly |x| = 5 is not equal to (y-z)
As per condition (2) x < 0.
Let x = -3, y = -8. Hence according to condition (1) z = -11.
|x| = 3.
(y-z) = 3
Hence both conditions are required.
- by sanju438
Wed Sep 24, 2008 12:56 pm- Forum: Data Sufficiency
- Topic: DS question
- Replies: 3
- Views: 2099