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Let's call rate of 1 Man = Rm and rate of 1 Woman = Rw We know, Rate * Time = Work Here, 3Rm (43) = 1 and 4Rw (43) = 1 So, Rm = 1 / (3 * 43) and Rw = 1 / (4 * 43) Combined rate of 7 Men = 7 / (3 * 43) Combined rate of 5 Women = 5 / (3 * 43) So combined rate of 7 men and 5 women, Rc = 7 / (3 * 43) + ...

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stmnt 1: insuff as you do not know the relation between r1 and r2 stmnt 2: insuff as you do not know the relation between p1 and p2 together, since p1 > p2 and r2 > r1 therefore p1r2 > p2r1 (population and representation cant be negative and both inequalities face the same direction so multiply dire...

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IMO E
Together,

case I:

1,2,3,....20,Ed, 22,23,24,25,26, Pam, 28,....(next 20) Total: 47

Case II:

1,2,3,....14, Pam, 16, 17,18,19,20, Ed, 22,23,24,25,...35: Total: 35

Two answers. Hence, insufficient.

Hope this helps.

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Negative solution -2x<-2 x>2 This is incorrect. This translates into x > 1. (although this doesn't change the outcome, one must be careful :-) ) stmnt 2: As you have said, stmnt 2 translates into (x-7)(x-3) >= 0 "these are boundary points, on a number line." These are indeed boundary cond...

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Yes indeed. let's put the probability of selecting both red marbles: {8 / (8+y)}{7/(7+y)} probability of 1 of each color: {8 / (8+y)}{y/(7+y)} what you need to find out in this question is: {8 / (8+y)}{7/(7+y)} > {8 / (8+y)}{y/(7+y)} which means 56 / {(8+y)(7+y)} > 8y / {(8+y)(7+y)} which means 56 >...

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let's put the probability of selecting both red marbles: {8 / (8+y)}{7/(7+y)} probability of 1 of each color: {8 / (8+y)}{y/(7+y)} what you need to find out in this question is: {8 / (8+y)}{7/(7+y)} > {8 / (8+y)}{y/(7+y)} which means 56 / {(8+y)(7+y)} > 8y / {(8+y)(7+y)} which means 56 > 8y which me...

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Understood. one last que

x<-8 and x>y contradict each another making this case invalid.

do you mean x <-8 and x >-8 (rather than x >y) contradict here?

Thanks a bunch.