Search found 29 matches
600 - 660...the mystery continues
I appeared 2nd time yesterday after my first attempt. Indian Male IT. Around 12 years experience. Good profile. 1st : 600 Q - 44, V - 28 2nd : 660 Q - 49, V - 32 1st: I originally started my preparation around 3 years ago but then stopped due to various personal reasons. Then I started preparing aga...
- by gmatIntent
Thu Dec 29, 2011 11:51 pm- Forum: I just Beat The GMAT!
- Topic: 600 - 660...the mystery continues
- Replies: 0
- Views: 1527
List of Redundancies
Some of the list of redundancies I've noted down during my preparation: Thought it would be helpful to others as well. 1. now currently temperate areas 2. Joachim Raff can never regain popularity again 3. Cost amounts to a sum less than 1 million. 4. as big as 30 feet long 5. Cost of food is expecte...
- by gmatIntent
Mon Dec 19, 2011 2:34 am- Forum: Sentence Correction
- Topic: List of Redundancies
- Replies: 0
- Views: 1261
Temperature of the moth
Which of the following most logically completes the passage? Each species of moth has an optimal body temperature for effective flight, and when air temperatures fall much below that temperature, the moths typically have to remain inactive on vegetation for extended periods, leaving them highly vuln...
- by gmatIntent
Thu Nov 24, 2011 3:05 am- Forum: Critical Reasoning
- Topic: Temperature of the moth
- Replies: 2
- Views: 1318
My comments about the legitimacy of the question were in reference to a different thread, in which statement 2 had apparently been transcribed incorrectly. In the other thread, the weight of the heavier pumpkins is EQUAL TO their number, an impossible scenario: http://www.beatthegmat.com/pumpkins-t...
- by gmatIntent
Thu Nov 24, 2011 2:50 am- Forum: Data Sufficiency
- Topic: Pumpkin patch
- Replies: 7
- Views: 2433
(1) There are five more heavier pumpkins than lighter pumpkins. Since the average is 12> 10, we can conclude that the value of r > 10. from the statement y = x +5 r = (2x/y) + 12 = (2*(y-5)/y) + 12. Insufficient! as we don't know the value of y. I don't get how you concluded that r > 10. Can you pl...
- by gmatIntent
Wed Nov 23, 2011 2:36 am- Forum: Data Sufficiency
- Topic: Pumpkin patch
- Replies: 7
- Views: 2433
Pumpkin patch
A pumpkin patch contains x pumpkins that weigh 10 pounds each and y pumpkins that weigh r pounds each. If the average (arithmetic mean) weight of the pumpkins is 12 pounds, what is the value of r? (1) There are five more heavier pumpkins than lighter pumpkins. (2) The weight in pounds of each of the...
- by gmatIntent
Tue Nov 22, 2011 6:17 am- Forum: Data Sufficiency
- Topic: Pumpkin patch
- Replies: 7
- Views: 2433
How did you so quickly find out the ranges? It took quite sometime for me to get that. :( I am guessing you did it the same way I did, you're given R is a 3 digit number. If R=1000, 3R = 3000. So we are looking at options < 3000 Possible cases, 800-899 | 1800-1899 | 2800-2899 After this, we just ne...
- by gmatIntent
Tue Nov 22, 2011 3:40 am- Forum: Data Sufficiency
- Topic: Hundreds digit of R?
- Replies: 5
- Views: 1705
Statement 1: Hundreds digit of 3R is 8. THink of it this way 3*(some 3 digit numbers) = X8XX Possible Cases; 3R can be between 801-897 (R between 267-299 (or) 3R can be between 1800 - 1899 (R between 600 - 633) (or) 3R can be between 2802-2898 ( R between 934 - 966) Hundreds place can be 2 or 6 or ...
- by gmatIntent
Tue Nov 22, 2011 2:53 am- Forum: Data Sufficiency
- Topic: Hundreds digit of R?
- Replies: 5
- Views: 1705
Hundreds digit of R?
Given that R is positive three-digit integer, what is the hundreds digit of R?
1. The hundreds digit of 3R is 8
2. (R+1) results in a number with the hundreds digit of 9.
[spoiler]OA : C[/spoiler]
Source : 800score.com
- by gmatIntent
Tue Nov 22, 2011 2:03 am- Forum: Data Sufficiency
- Topic: Hundreds digit of R?
- Replies: 5
- Views: 1705
Check the attachment of the original post by gmat009. It shows the diameter as 20.gmatpup wrote:where are we getting 10 as the radius?
Thanks!!
Thanks
- by gmatIntent
Thu Nov 10, 2011 9:04 pm- Forum: Problem Solving
- Topic: Semi-circle problem
- Replies: 22
- Views: 12876
Since each lane is 6 feet wide, we need to consider the shortest possible distance, imagine if a vehicle were to pass at the extreme left end of the lane for the figure you have drawn, it obviously violates the height clearance, if it asked for the maximum possible height we could just take the rad...
- by gmatIntent
Thu Nov 10, 2011 10:04 am- Forum: Problem Solving
- Topic: Semi-circle problem
- Replies: 22
- Views: 12876
Since you have drawn 2 cases here, let us use Case 2 as an example, If you said height permitted can be 9.5-1 = 8.5. Imagine a vehicle with height 8.5 travelled at the left extreme of the road (as drawn in Case 1), the height permitted would be only 8, if a vehicle with height 8.5 travels, it viola...
- by gmatIntent
Thu Nov 10, 2011 3:55 am- Forum: Problem Solving
- Topic: Semi-circle problem
- Replies: 22
- Views: 12876
Since each lane is 6 feet wide, we need to consider the shortest possible distance, imagine if a vehicle were to pass at the extreme left end of the lane for the figure you have drawn, it obviously violates the height clearance, if it asked for the maximum possible height we could just take the rad...
- by gmatIntent
Thu Nov 10, 2011 2:23 am- Forum: Problem Solving
- Topic: Semi-circle problem
- Replies: 22
- Views: 12876
Why are we considering only the line perperndicular to X? Why not another line can be 3 feet away from both sides of the traffic lane?
What am I doing wrong?
Refer attached diagram.
- by gmatIntent
Thu Nov 10, 2011 2:08 am- Forum: Problem Solving
- Topic: Semi-circle problem
- Replies: 22
- Views: 12876
- by gmatIntent
Sun Oct 23, 2011 10:43 pm- Forum: Sentence Correction
- Topic: Clarification on Adverb - Adjective
- Replies: 4
- Views: 2644