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Birthday Probability
If there are 85 students in a statistics class and we assume that there are 365 days in a year, what is the probability that at least two students in the class have the same birthday (assuming birthdays are distributed independently)? a)85/365 * 84/364 b)1/365 * 1/364 c)1-(85!/365!) d)1-(365!/(280!*...
- by kannan007
Sun Aug 05, 2012 9:11 am- Forum: Problem Solving
- Topic: Birthday Probability
- Replies: 1
- Views: 1024
the prime building block of 10 is 2 and 5..we have 2 in abundance,so count the 5..
60/5=12
then 25 contain an extra 5,50 contain an extra 5(5*2*5)..so 2 5's
total 12+2=14
- by kannan007
Sat Jun 16, 2012 1:57 am- Forum: Problem Solving
- Topic: Trailiiiiiing zer0s
- Replies: 21
- Views: 12026
use plugig that satisfies first statement
x=-1/y=0 x+y =-1
x=1/y=0 x+y=1
so not sufficient
The same plugin helps to proove that 2nd statement is not sufficient:-)
The same plugin helps to proove that statement 1+statement 2 is not sufficient,hence answer E.
- by kannan007
Sat Jun 16, 2012 1:40 am- Forum: Data Sufficiency
- Topic: Inequality
- Replies: 30
- Views: 13355
In 100 Pound .There is 99 pound water and say 1 pound C.
As water evaporates,its still 1 pound C which is (100-98%)2% of renaming mass.
2/100*Total weight=1
Total Weight=50 Pounds
- by kannan007
Sat May 19, 2012 2:20 am- Forum: Problem Solving
- Topic: Cucumber
- Replies: 26
- Views: 20407
My approach would be:- The Number of ways in which this can happen i mean selection a jury in of 12 members from a group of 10 men and 5 women are 5 women and 7 men 4 women and 8 men 3 women and 9 men 2 women and 10 men We need a minimum of 8 men..so 3 out of 4 events.3/4 approx =0.75 and the answer...
- by kannan007
Fri Mar 30, 2012 6:55 am- Forum: Problem Solving
- Topic: I Suck at Probability need desperate help
- Replies: 69
- Views: 58759
my calculations goes as below..
of the remaining money chole receives 2 times as bob..
so bob get (32/2=16 of the remaning money )and he get a 4 as well..so 16+4=20!!
- by kannan007
Mon Mar 26, 2012 8:33 am- Forum: Problem Solving
- Topic: Tough word problem - dividing $
- Replies: 69
- Views: 33871