Search found 5 matches
My answer is D. A.) I am translating this to mean that if there is �any� prime number in N, then the p^2 version of that prime is also in N. Meaning � Every prime is squared. If this is the correct interpretation, then this is sufficient. A perfect square, when reduced to primes, will have ev...
- by DarylB
Mon Jun 27, 2011 5:55 am- Forum: Data Sufficiency
- Topic: Prime & Square
- Replies: 29
- Views: 13186
for question 2, A is a decent inference given the description of author's style. I eliminated B-D with these lines: B- her fictive world remains strikingly akin to that real one reflected in the daily newspapers (not much of a romance novel) C- ..some of it appears to come from her own direct observ...
- by DarylB
Sun Apr 03, 2011 11:55 am- Forum: Reading Comprehension
- Topic: Joyce Carol Oates
- Replies: 37
- Views: 24924
stmt1: If n=1 a^1-b^1=(a-b), divisible by (a-b). If n=2 a^2-b^2 =(a+b)(a-b), divisible by (a-b). Stmt 1 NS. stmt2: If n=1 a^1+b^1 = a+b, divisible by (a+b). If n=2, so we have (a^2+b^2), and if a=b=1. yes, divisible by (a+b). a=b=2. yes, divisible by (a+b). a=b=10. yes, divisible by (a+b). a!=b, no,...
- by DarylB
Sun Apr 03, 2011 7:07 am- Forum: Data Sufficiency
- Topic: DS + nth power
- Replies: 58
- Views: 23951
That's the way I did it, too. Well done, kamu, that's the quickest way.kamu wrote:Bob took $4 + 1/3 of leftover..
that implies 2/3rds is left for Chloe..
if 2/3 of leftover = $32
1/3 of leftover = $16
$16+$4 = $20.
- by DarylB
Sun Mar 13, 2011 12:57 pm- Forum: Problem Solving
- Topic: Tough word problem - dividing $
- Replies: 69
- Views: 33887
So the OA here is E! @uwhusky: just stumbled upon it in the Beat The GMAT Practice Questions ... While I don't have a specific set of questions with modifiers, I have seen quite a few in this resource, especially one really tough one with Italians and Slavs... If I find it again, I'll post it! Anyw...
- by DarylB
Sat Mar 05, 2011 6:57 am- Forum: Sentence Correction
- Topic: Speed limit - long one!
- Replies: 282
- Views: 109928