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Need answers for MGMAT RC

Can somebody post the answers for Passage F and G of Manhattan Gmat Reading Comprehension Chapter 7.
My Gmat book does not have those.

by ankush123251

Fri Jan 20, 2012 3:26 am
Forum: Reading Comprehension
Topic: Need answers for MGMAT RC
Replies: 0
Views: 1003

My approach,

R = (-3,1)

Since y = -x is perpendicular bisector of RS point S will be symmetrical about line y = -x.Thus point S will be (-1,3).
Again Y axis is perpendicular bisector of ST.Thus,T will be symmetrical to S about Y axis.
Thus,
T = (1,3)

by ankush123251

Mon Dec 19, 2011 11:47 pm
Forum: Problem Solving
Topic: Grockit tough problem
Replies: 18
Views: 10971

Each child has 2 options being a boy or a girl.
So total number of outcomes = 2* 2 * 2 * 2 =16.

Number of ways in which 4 children will have 2 boys and 2 girls = 4!/2!* 2! = 6.

So,
Probability = 6/16 =3/8

QA is A.

by ankush123251

Mon Dec 19, 2011 11:26 pm
Forum: Problem Solving
Topic: Probability: Boy or Girl?
Replies: 8
Views: 24117

The method that i used is:
Probability of choosing Joshua = 1/6
Probability of choosing Jose after Joshua = 1/5
Since both of them are to be present,
Probability = 1/6 * 1/5
Now since Jose could have been chosen first,
Probability = 1/6 * 1/5 + 1/6 * 1/5 = 1/15.

by ankush123251

Mon Dec 19, 2011 11:22 pm
Forum: Problem Solving
Topic: Joshua and Jose work at an auto repair center
Replies: 6
Views: 2440

Hi GMATGuru, I beleive we have a formula of dividing (m + n ) people into two groups with m and n people respectively = (m + n)!/(m! * n!) Now,if each of these groups are identical we divide by 2!. So if i apply this formula to the above problem, No of ways = 8!/(2!*2!* 2!*2!*4!) =105. Divided by 4!...

by ankush123251

Mon Dec 19, 2011 10:50 pm
Forum: Problem Solving
Topic: Forming Teams
Replies: 11
Views: 6191

Nice explanation..thanks

by ankush123251

Mon Dec 19, 2011 10:34 pm
Forum: Problem Solving
Topic: Median - PS
Replies: 8
Views: 2026

QA is 12 as i mentioned in my earlier post.

by ankush123251

Mon Dec 19, 2011 6:20 am
Forum: Problem Solving
Topic: how many factors?
Replies: 9
Views: 4208

Total units of Work = 10 * 16 =160 units.
So,if 8 machines are used,time taken = Work/Number of machines =160/8 =20.
Option B

by ankush123251

Mon Dec 19, 2011 6:05 am
Forum: Problem Solving
Topic: help....
Replies: 3
Views: 2594

I cannot understand the median problem though.So guessed the answer.Can anyone solve it?Experts?

by ankush123251

Mon Dec 19, 2011 5:37 am
Forum: Problem Solving
Topic: Got lots of questions
Replies: 15
Views: 5639

Hi,
please find attached my answers to your problems.
Please reply if i have made mistake in any of them.

by ankush123251

Mon Dec 19, 2011 5:24 am
Forum: Problem Solving
Topic: Got lots of questions
Replies: 15
Views: 5639

Oh ok.I can relate that to for a given perimeter,square has maximum area and for given area it has minimum perimeter.

by ankush123251

Mon Dec 19, 2011 4:21 am
Forum: Problem Solving
Topic: Two Unique Problems
Replies: 6
Views: 1187

Followed this method:
Total number of outcomes = 12C4 =495
No. of favorable outcomes = 6C4 + 6C3 * 3C1 + 6C2 * 4C2 + 6C1 * 5C3 + 6C4(all 4 males + 3 males and 1 female and so on) =240
Thus,
Probability = 240/495 =16/33.

by ankush123251

Mon Dec 19, 2011 4:16 am
Forum: Problem Solving
Topic: married couples
Replies: 8
Views: 4489

Area of shaded region = Area of circle - Area of Sector

1)Gives area of circle but nothing about sector.Not sufficient.
2)Each angle of triangle =60.
Thus area of sector = 60/360 * Area of circle.
Not sufficient.

Combining you can solve the question.Do not calculate the actual answer.OA is C

by ankush123251

Mon Dec 19, 2011 3:55 am
Forum: Problem Solving
Topic: geometry question data sufficency
Replies: 4
Views: 1349

Fractions that are between 0 and 1 behave like this:
If you square a fraction the value decreases.
Thus,
1/2 * 1/2 = 1/4.
Thus,
s<r.Thus options A,B,E eliminated.
Further if you take the square root,the value of the fraction increases.
Thus option D.

by ankush123251

Mon Dec 19, 2011 3:47 am
Forum: Problem Solving
Topic: OG 12 Problem - Please help
Replies: 2
Views: 1222

@Brent-Isn't that the exactly reason why we have not done 12P2 and 12C2 because the order does not matter!!

by ankush123251

Mon Dec 19, 2011 3:25 am
Forum: Problem Solving
Topic: number of handshakes
Replies: 5
Views: 4063