Search found 12 matches
Good work! IMO 5+...also, the number of cities surveyed would help...we don't know how many cities were surveyed...the city could be ranked 14th out of 15.
- by showoff16884
Thu Nov 15, 2007 5:57 pm- Forum: GMAT Essays (AWA)
- Topic: Argument Evaluation
- Replies: 7
- Views: 17519
- by showoff16884
Wed Nov 14, 2007 8:56 pm- Forum: Problem Solving
- Topic: Researcher's Code
- Replies: 3
- Views: 1719
@ spidy
Thank you! That was very stupid of me...I was wondering how mass was to be converted to volume!!!
- by showoff16884
Tue Nov 13, 2007 8:34 pm- Forum: Problem Solving
- Topic: Conversions
- Replies: 2
- Views: 1572
Conversions
The mass of 1 cubic meter of a substance is 800 kilograms under certain conditions, what is the volume, in cubic centimeter, of 1 gram of this substance under these conditions?
(1 kilogram = 1,000 grams & 1 cubic meter = 1,000,000 cubic centimeters)
- by showoff16884
Tue Nov 13, 2007 7:46 pm- Forum: Problem Solving
- Topic: Conversions
- Replies: 2
- Views: 1572
X is greatest when Y = 0.
X = 4th root of 100, which is between 3 & 6
(you know x has to be greater than 3, because when x=3, x^4 = 81 and x can't be greater than 6. You only have one option then)
- by showoff16884
Mon Nov 12, 2007 5:22 pm- Forum: Problem Solving
- Topic: One more..
- Replies: 1
- Views: 1524
- by showoff16884
Mon Nov 12, 2007 4:43 pm- Forum: Problem Solving
- Topic: From GMAT Prep
- Replies: 2
- Views: 1586
Researcher's Code
A researcher plans to identify each participant in a certain medical experiment with a code consisting of either a single letter or a pair of distinct letters written in alphabetical order. What is the least number of letters that can be used if there are 12 participants, and each participant is to ...
- by showoff16884
Mon Nov 12, 2007 4:39 pm- Forum: Problem Solving
- Topic: Researcher's Code
- Replies: 3
- Views: 1719
Gabriel is right. The question is asking for the the divisors for each integer
P3 > 1, P1, P2 & P3
NP > 1, N, P & NP
4 divisors for each integer. Answer choice E
- by showoff16884
Sun Nov 11, 2007 7:45 pm- Forum: Problem Solving
- Topic: Can 1 and the number itself be counted as divisors?
- Replies: 2
- Views: 2080
I guess this is a much simpler way to look at it...
5^21*4^11 = 2*10^n
5^21*2^22 = 2*2^n*5^n
5^21*2^21*2 = 5^n*2^n*2
hence, n = 21
I hope you guys understand!
Cheers!
- by showoff16884
Sun Nov 11, 2007 7:36 pm- Forum: Problem Solving
- Topic: GMAT Practice Paper 1 n0. 1
- Replies: 9
- Views: 2319
- by showoff16884
Tue Nov 06, 2007 5:29 pm- Forum: Problem Solving
- Topic: PS
- Replies: 4
- Views: 2493
Problem 1
Here is the link to solution to problem # 1
http://www.beatthegmat.com/stuck-on-thi ... t6439.html
Its a tricky one!
- by showoff16884
Mon Nov 05, 2007 9:15 am- Forum: Problem Solving
- Topic: Practice Test Problems
- Replies: 3
- Views: 1600
Practice Test Problems
Please help explain the answers to the following practice questions: 1. If [(1/5)^m *(1/4)^18] = [1/(2(10)^35)], what is the value of m? A. 17 B. 18 C. 34 D. 35 E. 36 2. If (2^x) - (2^(x-2)) = (3(2^13)), x=? A. 9 B. 11 C. 13 D. 15 E. 17 3. A perimeter of a certain isosceles right triangle is 16+(16 ...
- by showoff16884
Sun Nov 04, 2007 3:45 pm- Forum: Problem Solving
- Topic: Practice Test Problems
- Replies: 3
- Views: 1600