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If 4 different prime numbers are factors of 2n then one of the 4 numbers is definitely 2. That would mean there are 3 numbers which are factors of n.
If 4 numbers a b c and d are prime factors of n then the prime factors of n^2 are a^2, b^2, c^2 and d^2.
- by adaftprig
Fri Nov 23, 2012 7:25 am- Forum: Problem Solving
- Topic: number prop
- Replies: 3
- Views: 1127