soda

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soda

by ddm » Wed Aug 27, 2008 3:36 pm
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by kuroneko1313 » Wed Aug 27, 2008 3:50 pm
I couldn't come up with anything but D... Water costs zero so shouldn't it be accounted for..?

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by somail » Wed Aug 27, 2008 3:59 pm
I think the reason E is correct over D, is because revenue in this case is based off of total liters. So the final equation must contain the total number of liters of water.

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by parallel_chase » Wed Aug 27, 2008 4:02 pm
water - w
syrup - m

for every liter of syrup each liter of water is required

total mixture = wm+m

selling price = j per liter
Therefore = j(wm+m)

cost price = k per liter
since water costs nothing total cost will be km

gross profit = selling price - cost price

=> j(wm+m) - km
=> jm(w+1) - km

Hence E is the answer.

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by mehravikas » Wed Aug 27, 2008 11:10 pm
Awesome explanation :-)
parallel_chase wrote:water - w
syrup - m

for every liter of syrup each liter of water is required

total mixture = wm+m

selling price = j per liter
Therefore = j(wm+m)

cost price = k per liter
since water costs nothing total cost will be km

gross profit = selling price - cost price

=> j(wm+m) - km
=> jm(w+1) - km

Hence E is the answer.