[(8^2)(3^3)(2^4)]/(96^2)
i understand the concept of breaking down 96^2 in terms of the numerator, but how do you factor it appropriately? maybe I'm missing a simple concept, but the answer is vague in the explanations section.
thx
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I don't have OG with me, so can't look at answers given there.
And, I don't understand your concern. You seem to be fine with breaking down 96 into factors. What are you looking for?
And, I don't understand your concern. You seem to be fine with breaking down 96 into factors. What are you looking for?
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when it comes to breaking down powers of integers -- if you don't immediately see any tricks or shortcuts, just break all the integers down into primes. (in fact, this should almost be a knee-jerk reaction -- if you see powers of specific whole numbers, your brain should yell, "primes!")DCS80 wrote:[(8^2)(3^3)(2^4)]/(96^2)
i understand the concept of breaking down 96^2 in terms of the numerator, but how do you factor it appropriately? maybe I'm missing a simple concept, but the answer is vague in the explanations section.
thx
so, here, that would include not only breaking down the 96 in the denominator, but also breaking the 8 (in the numerator) down into more 2's.
Ron has been teaching various standardized tests for 20 years.
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Pueden hacerle preguntas a Ron en castellano
Potete chiedere domande a Ron in italiano
On peut poser des questions à Ron en français
Voit esittää kysymyksiä Ron:lle myös suomeksi
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Quand on se sent bien dans un vêtement, tout peut arriver. Un bon vêtement, c'est un passeport pour le bonheur.
Yves Saint-Laurent
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Learn more about ron