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by thp510 » Sat Feb 26, 2011 8:24 am
x + 3 < n - 1

How do you turn the above equation into x+n<2n-4 ???

I did the following.
x-n < -4
-1(x-n) > (-4)-1
n-x > 4

Am I missing something extremely obvious? This seems too easy to get stumped on.
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by anshumishra » Sat Feb 26, 2011 8:46 am
thp510 wrote:x + 3 < n - 1

How do you turn the above equation into x+n<2n-4 ???

I did the following.
x-n < -4
-1(x-n) > (-4)-1
n-x > 4

Am I missing something extremely obvious? This seems too easy to get stumped on.
x+3 < n -1
subtract 3 both sides
x < n-4
add n both sides
x+n < n+n -4
=> x+n < 2n -4
Thanks
Anshu

(Every mistake is a lesson learned )
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by Night reader » Sat Feb 26, 2011 8:49 am
you are given inequality not equation, x + 3 < n - 1 could be rewritten as x < n - 4 OR x + n < n+n - 4 which is equivalent to x + n < 2n - 4
thp510 wrote:x + 3 < n - 1

How do you turn the above equation into x+n<2n-4 ???

I did the following.
x-n < -4
-1(x-n) > (-4)-1
n-x > 4

Am I missing something extremely obvious? This seems too easy to get stumped on.
My knowledge frontiers came to evolve the GMATPill's methods - the credited study means to boost the Verbal competence. I really like their videos, especially for RC, CR and SC. You do check their study methods at https://www.gmatpill.com
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by thp510 » Sat Feb 26, 2011 9:16 am
Wow, totally forgot you can add an n out of nowhere. Whoops. Thanks.
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