Manhattan Challenge Problem

This topic has expert replies
Master | Next Rank: 500 Posts
Posts: 174
Joined: Mon Mar 26, 2007 5:51 am
Thanked: 1 times

Manhattan Challenge Problem

by 800GMAT » Tue Jun 19, 2007 2:41 pm
One smurf and one elf can build a treehouse together in two hours, but the smurf would need the help of two fairies in order to complete the same job in the same amount of time. If one elf and one fairy worked together, it would take them four hours to build the treehouse. Assuming that work rates for smurfs, elves, and fairies remain constant, how many hours would it take one smurf, one elf, and one fairy, working together, to build the treehouse?

(A) 5/7

(B) 1

(C) 10/7

(D) 12/7

(E) 22/7

User avatar
Master | Next Rank: 500 Posts
Posts: 277
Joined: Sun Jun 17, 2007 2:51 pm
Location: New York, NY
Thanked: 6 times
Followed by:1 members

by givemeanid » Tue Jun 19, 2007 3:59 pm
Is it (D)? 12/7

Master | Next Rank: 500 Posts
Posts: 103
Joined: Sun Jun 10, 2007 7:10 pm
Location: Brooklyn, NY
Thanked: 2 times

by jrbrown2 » Tue Jun 19, 2007 4:36 pm
(1S + 1E)*2Hrs = Job Complete
(1S + 2F)*2Hrs = Job Complete

So 1 Elf does the Job of 2 fairies ( 1E = 2F)

(1E + 1F)*4 Hrs = Job Complete (Looking at this equation, it can be seen that in order for the job to be completed in 2 hours, you'll need twice as many elves and fairies

2(1E+1F)*2Hrs = Job Complete so,
(2E + 2F)*2Hrs = Job Complete (equating this equation with the 2nd equation, it can be seen that 1S = 2E. 1E = 2F so 1S = 4F

(1E+1S+1F)*X Hrs = Job complete
Equate this w/ 2nd equation:

(E+S+F)*X Hrs = (1S + 2F)*2Hrs

(2F+4F+F)*X Hrs = (4F + 2F)*2Hrs
7F*X Hrs = 12 F*Hrs

X = 12/7 Hrs (D)