A grocer stacked oranges in a pile. the bottom layer was rectangular with 3 rows of 5 oranges each. In the second layer from the bottom, each orange rested on 4 oranges from the bottom layer and in the third layer each orange rested on 4 oranges from the second layer. Which of the following is the the maximum number of oranges that could have been in the third layer.
a. 5
b. 4
c. 3
d. 2
e. 1
OA C
how do i get the correct anwser
ps
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I'm guessing the quickest way is to draw it out. It took me about 20 seconds to draw the diagram and find the correct answer.baller12q wrote:A grocer stacked oranges in a pile. the bottom layer was rectangular with 3 rows of 5 oranges each. In the second layer from the bottom, each orange rested on 4 oranges from the bottom layer and in the third layer each orange rested on 4 oranges from the second layer. Which of the following is the the maximum number of oranges that could have been in the third layer.
a. 5
b. 4
c. 3
d. 2
e. 1
OA C
how do i get the correct anwser
A good general rule to follow is that when you've got a word problem that translates into a picture, draw it out. Many test takers find that visual representations make questions much easier to handle.
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F = First row oranges
S = Second row oranges
T = third row oranges
F F F F F
S S S S
F F F F F
S S S S
F F F F F
Since the second row is
S S S S
T T T
S S S S
There are maximum of 3 T
Hope this helps
S = Second row oranges
T = third row oranges
F F F F F
S S S S
F F F F F
S S S S
F F F F F
Since the second row is
S S S S
T T T
S S S S
There are maximum of 3 T
Hope this helps
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Could not find any way other than to draw a pic
First layer has 3 rows of 5 oranges each. Draw _ and a space for each orange in row 1.
Each orange in Second layer touches 4 oranges in 1st layer.
so max of 8 oranges. Draw squares connecting 4 _. This becomes ur 2nd row.
For third row, draw another set of squares which connect 4 squares from the 2nd layer. If u want u can choose to draw a rhombus or X to denote the connection.
Count the squares/X in 3d row. It will be 3.
Let me know if u can t picture this.
thanks
-V
First layer has 3 rows of 5 oranges each. Draw _ and a space for each orange in row 1.
Each orange in Second layer touches 4 oranges in 1st layer.
so max of 8 oranges. Draw squares connecting 4 _. This becomes ur 2nd row.
For third row, draw another set of squares which connect 4 squares from the 2nd layer. If u want u can choose to draw a rhombus or X to denote the connection.
Count the squares/X in 3d row. It will be 3.
Let me know if u can t picture this.
thanks
-V
- Stuart@KaplanGMAT
- GMAT Instructor
- Posts: 3225
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Here's my diagram - fear my art skills!
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