A company hired a printer to produce a total of x + 1 envelopes. The job consisted of two types of envelopes, 2$ envelopes and 5$ envelopes. If the company requested 3 more 2$ envelopes than 5$ envelopes, which of the following expression denotes the cost, in cents, of total x + 1 envelopes.
a. 3x + 1
b. (7x-2)/2
c. 11x + 31
d. (7x - 6)/2
e. (13x + 3)/2
pls explain
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Printer - envelopes
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RikaMueller
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Say, number of $5 envelopes = n => Number of $2 envelopes = (n + 3)
Thus, total number of envelopes = n + (n + 3) = 2n + 3 = x + 1 => n = (x - 2)/2
Now, cost of all the envelopes = ($5)*(n) + ($2)*(n + 3) = $(5n + 2n + 6) = $(7n + 6) = $[7*{(x - 2)/2} + 6] = $[(7x - 2)/2]
The correct answer is B.
(I believe either the prices are in cents or the cost is asked in dollar. Please check the question.)
Thus, total number of envelopes = n + (n + 3) = 2n + 3 = x + 1 => n = (x - 2)/2
Now, cost of all the envelopes = ($5)*(n) + ($2)*(n + 3) = $(5n + 2n + 6) = $(7n + 6) = $[7*{(x - 2)/2} + 6] = $[(7x - 2)/2]
The correct answer is B.
(I believe either the prices are in cents or the cost is asked in dollar. Please check the question.)
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RikaMueller
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Thanks.
But from:
$[7*{(x - 2)/2} + 6] = $[(7x - 2)/2]
I would get $[(7x - 1)/2] as -14/2 + 6 = -1.
But from:
$[7*{(x - 2)/2} + 6] = $[(7x - 2)/2]
I would get $[(7x - 1)/2] as -14/2 + 6 = -1.
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RikaMueller
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Rahul@gurome
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Yes.RikaMueller wrote:Thanks.
But from:
$[7*{(x - 2)/2} + 6] = $[(7x - 2)/2]
I would get $[(7x - 1)/2] as -14/2 + 6 = -1.
But then you have to add -1 with 7x/2, which results in [(7x/2) - 1], which is not same as (7x -1)/2!
Follow me,
[7*{(x - 2)/2} + 6] = [(7x - 14)/2 + 6] = [(7x/2) - 7 + 6] = [(7x/2) - 1] = [(7x - 2)/2]
Hope it helps!
Rahul Lakhani
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RikaMueller
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We can plug in our own values:RikaMueller wrote:A company hired a printer to produce a total of x + 1 envelopes. The job consisted of two types of envelopes, 2¢ envelopes and 5¢ envelopes. If the company requested 3 more 2¢ envelopes than 5¢ envelopes, which of the following expressions denotes the cost, in cents, of the total x + 1 envelopes ?
A)3x+1
B)(7x-2)/2
C)11x+31
D)(7x-6)/2
E)(13x+3)/2
pls explain
2 5¢ envelopes requested.
5 2¢ envelopes requested (since 3 more 2¢ envelopes are requested).
2+5 = 7 total envelopes requested.
Thus, x+1 = 7, x = 6.
Cost = 2*5 +5*2 = 20. This is our target.
Now we plug x=6 into all the answer choices to see which yields our target of 20.
Only answer choice B works:
(7x-2)/2 = (7*6-2)/2 = 20.
The correct answer is B.
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I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
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