307. Tom reads at an average rate of 30 pages per hour, while Jan reads at an average rate of 40 pages per hour. If Tom starts reading a novel at 4:30, and Jan begins reading an identical copy of the same book at 5:20, at what time will they be reading the same page?
A. 9:30
B. 9:00
C. 8:40
D. 7:50
E. 7:00
Tom reads at an average rate of 30 pages per hour, whil
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In 1 minute,varun289 wrote:307. Tom reads at an average rate of 30 pages per hour, while Jan reads at an average rate of 40 pages per hour. If Tom starts reading a novel at 4:30, and Jan begins reading an identical copy of the same book at 5:20, at what time will they be reading the same page?
- Tom reads 1/2 page
Jan reads 2/3 page
In 50 minutes Tom has already read 50/2 = 25 pages
Say, after t minutes from 5:20, they'll be reading the same page.
Then in t minutes, Jan has to read 25 pages and the pages Tom have read in t minutes.
Hence, (25 + t/2) = 2t/3 ---> (2t/3 - t/2) = 25 ---> t/6 = 25 ---> t = 150
150 minutes after 5:20 = 2 hours 30 minutes after 5:20 = 7:50
The correct answer is D.
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From 4:30 to 5:20, the number of pages read by Tom = r*t = 30(5/6) = 25.varun289 wrote:307. Tom reads at an average rate of 30 pages per hour, while Jan reads at an average rate of 40 pages per hour. If Tom starts reading a novel at 4:30, and Jan begins reading an identical copy of the same book at 5:20, at what time will they be reading the same page?
A. 9:30
B. 9:00
C. 8:40
D. 7:50
E. 7:00
From 5:20pm on, Jan COMPETES with Tom.
When elements compete, SUBTRACT THE RATES.
Jan's rate - Tom's rate = 40-30 = 10.
This is the CATCH-UP rate: the rate at which Jan CATCHES UP to Tom.
Because Jan reads 10 more pages than Tom every hour, she CATCHES-UP by 10 pages every hour.
Time for Jan to catch up by 25 pages = w/r = 25/10 = 2.5 hours.
Since Jan starts to read at 5:20pm, she catches-up to Tom at 5:20pm + 2:30 = 7:50pm.
The correct answer is D.
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How to get the above equation? can you explain?Anurag@Gurome wrote: Hence, (25 + t/2) = 2t/3 ---> (2t/3 - t/2) = 25 ---> t/6 = 25 ---> t = 150
In such cases how to form equations?
Tom - 30pages/hr
Jan - 40pages/hr
Jan would have read 10 pages more by the end of the hour
Tom starts at 4:30
by 5:20 he would have read 25 pages and Jan will start reading nw
If it takes ,
1hr - 10pages (Jan needs 1hr to cover a difference of 10pages)
xhrs - 25pages
x=2hr 30mins
5:20 + 2hrs30 mins = 7:50pm
Jan - 40pages/hr
Jan would have read 10 pages more by the end of the hour
Tom starts at 4:30
by 5:20 he would have read 25 pages and Jan will start reading nw
If it takes ,
1hr - 10pages (Jan needs 1hr to cover a difference of 10pages)
xhrs - 25pages
x=2hr 30mins
5:20 + 2hrs30 mins = 7:50pm
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Say, after t minutes from 5:20, they'll be reading the same page.nisagl750 wrote:How to get the above equation? can you explain?Anurag@Gurome wrote: Hence, (25 + t/2) = 2t/3 ---> (2t/3 - t/2) = 25 ---> t/6 = 25 ---> t = 150
Then in t minutes, Jan has to read 25 pages and the pages Tom have read in t minutes.
Now, in t minutes,
- Tom will read t/2 pages
Jan will read 2t/3 pages
Hence, (25 + t/2) = 2t/3 ---> (2t/3 - t/2) = 25 ---> t/6 = 25 ---> t = 150
Hope that helps.
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Ok so Tom has a head start of:
use S=Vt; P=30(50/60) = 25 pages
So assuming time clock starts to tick at 5:20
Tom's equation : S+25 = 30t
Other Guy's Equation: S=40t
Since they have to be at the same page both S are same
30t-25=40t
Which gives out t=2.5 hours : hence 7:50 Answer
use S=Vt; P=30(50/60) = 25 pages
So assuming time clock starts to tick at 5:20
Tom's equation : S+25 = 30t
Other Guy's Equation: S=40t
Since they have to be at the same page both S are same
30t-25=40t
Which gives out t=2.5 hours : hence 7:50 Answer