Mixtures
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- harshavardhanc
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7 Kgs of claynewton9 wrote:10kg of a mixture contains 30% sand and 70% clay. In order to make the mixture contain equal quantities of clay and sand. how much of the mixture is to be removed and replaced with pure sand?
3 Kgs of sand
make them equal. i.e 5Kgs each.
OR remove 2 Kgs of clay which will come from 20/7 kgs of the mixture.
Last edited by harshavardhanc on Wed Mar 31, 2010 11:41 am, edited 1 time in total.
Regards,
Harsha
Harsha
- harshavardhanc
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correct!newton9 wrote:Harsha,
You cannot directly take out clay or sand. That's the trick.
You have to take out the mixture and replace it with pure sand.
I was in hurry as my ride had come and I jumped the gun with that solution!
Anyway, yes that's the trick. you can only take out the mixture.
The correct answer will be that quantity of mixture which will have 2 kgs of clay.
Regards,
Harsha
Harsha
suppose you take out x kg of mixture and replace it with pure sand
so, amount of sand in x kg of mixture = 0.3x
and, amount of clay in x kg of mixture = 0.7x
add, x kg od sand in the mixture
so net sand = 3-0.3x+x
net clay=7-0.7x
hence, 3+0.7x = 7-0.7x
or, 1.4x=4
x=4/1.4=2.857..
so, amount of sand in x kg of mixture = 0.3x
and, amount of clay in x kg of mixture = 0.7x
add, x kg od sand in the mixture
so net sand = 3-0.3x+x
net clay=7-0.7x
hence, 3+0.7x = 7-0.7x
or, 1.4x=4
x=4/1.4=2.857..
- eaakbari
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There is an interesting formula I use that works with mixtures and weighted averages.
% of higher ratio - % of mean : % of mean - %of lower = lower :higher
Here we have 1 part containing 100% sand
1 part containing 30 % sand
what we want is 50 % sand
substitute in formula
100 - 50 : 50 - 30 = lower:higher
5:2 = lower :higher
That means the ratio of 30%mixture to pure sand is 5:2
The total weight has to be 10 kgs
5x+2x=7x
7x=10 ; x=10/7
Hence 5 x = 50/7
Hence we can find how many kgs would a 10 kg misture contain of the 30%misture
= 50/7
Therefore amount removed = 10 -50/7 = 20/7
which is the answer
% of higher ratio - % of mean : % of mean - %of lower = lower :higher
Here we have 1 part containing 100% sand
1 part containing 30 % sand
what we want is 50 % sand
substitute in formula
100 - 50 : 50 - 30 = lower:higher
5:2 = lower :higher
That means the ratio of 30%mixture to pure sand is 5:2
The total weight has to be 10 kgs
5x+2x=7x
7x=10 ; x=10/7
Hence 5 x = 50/7
Hence we can find how many kgs would a 10 kg misture contain of the 30%misture
= 50/7
Therefore amount removed = 10 -50/7 = 20/7
which is the answer
- harshavardhanc
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indeed, it's a good formula.eaakbari wrote:There is an interesting formula I use that works with mixtures and weighted averages.
% of higher ratio - % of mean : % of mean - %of lower = lower :higher
Here we have 1 part containing 100% sand
1 part containing 30 % sand
what we want is 50 % sand
substitute in formula
100 - 50 : 50 - 30 = lower:higher
5:2 = lower :higher
That means the ratio of 30%mixture to pure sand is 5:2
The total weight has to be 10 kgs
5x+2x=7x
7x=10 ; x=10/7
Hence 5 x = 50/7
Hence we can find how many kgs would a 10 kg misture contain of the 30%misture
= 50/7
Therefore amount removed = 10 -50/7 = 20/7
which is the answer
in cases like this one, however, you can save some more time by having a "birds eye view".
look at the percentages. one is 30 and the other one is 70. You want to make them equal. or 50-50.
Or you have to remove that 20% of clay.
Now, we know that 70% clay comes from 100% of mixture. Therefore, 20% will come from (20 * 100)/70.
or 200/7 % of the mixture OR 2/7 of the mixture.
Hence, the answer will be 2/7th of 10 = 20/7 . in fact it is even possible to do it orally
Regards,
Harsha
Harsha
- sanju09
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If x kg of the mixture is removed and replaced with pure sand, then the sand contents in the new 10 kg of mixture are [0.3 (10 - x) + x] kg and the clay contents in that are 0.7 (10 - x) kg, such thatnewton9 wrote:10kg of a mixture contains 30% sand and 70% clay. In order to make the mixture contain equal quantities of clay and sand. how much of the mixture is to be removed and replaced with pure sand?
[0.3 (10 - x) + x] = 0.7 (10 - x)
3 + 0.7 x = 7 - 0.7 x
1.4 x = 4
[spoiler]x = 20/7 kg[/spoiler]
The mind is everything. What you think you become. -Lord Buddha
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com
- sanju09
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to me, it's even betterharshavardhanc wrote:7 Kgs of claynewton9 wrote:10kg of a mixture contains 30% sand and 70% clay. In order to make the mixture contain equal quantities of clay and sand. how much of the mixture is to be removed and replaced with pure sand?
3 Kgs of sand
make them equal. i.e 5Kgs each.
OR remove 2 Kgs of clay which will come from 20/7 kgs of the mixture.
The mind is everything. What you think you become. -Lord Buddha
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com