pmcch wrote:For any positive x, y and z if x is n% of y and z is m% of y then what percentage must x be of z?
A. (n/m)%
B. (m × n)%
C. (100 / [m × n]) %
D. (100 × m/n)%
E. (100 × n/m)%
Let y=100.
Let n=200.
Since x is n% of y, x = 200% of 100 = 200.
Let m=400.
Since z is m% of y, z = 400% of 100 = 400.
Since x=200 and z=400, x is 50% of z.
Thus, our target is 50%.
Now we plug n=200 and m=400 into the answers to see which yields our target of 50%.
Only
E works:
(100 * n/m)% = ( 100 * 200/400 )% = 50%.
The correct answer is
E.
Algebraically:
Let y=100.
Since x is n% of y, x = (n/100) * 100 = n.
Since z is m% of y, z = (m/100) * 100 = m.
Question: x is what percent of z?
x/z * 100 = n/m * 100.
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