combined age

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combined age

by j_shreyans » Tue Jun 16, 2015 8:03 am
Joan, Kylie, Lillian, and Miriam all celebrate their birthdays today. Joan is 2 years younger than Kylie, Kylie is 3 years older than Lillian, and Miriam is one year older than Joan. Which of the following could be the combined age of all four women today?

51

52

53

54

55

OA54

I got this one right, still I need algebraic approach.

Please advise

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by Brent@GMATPrepNow » Tue Jun 16, 2015 8:08 am
Joan, Kylie, Lillian, and Miriam all celebrate their birthdays today. Joan is 2 years younger than Kylie, Kylie is 3 years older than Lillian, and Miriam is one year older than Joan. Which of the following could be the combined age of all four women today?
A) 51
B) 52
C) 53
D) 54
E) 55
Here's a solution using ONE VARIABLE.

Let's let Joan's age = J (aside: we could assign the initial variable to someone else's age, but at first glance Joan appears to be one of the younger people, and it's often easier to assign the first variable to the smallest/smaller value)

Joan is 2 years younger than Kylie: So, Kylie's age = J+2
Kylie is 3 years older than Lillian: In other words, Lillian's age is 3 years less than Kylie's age. So, Lillian's age = (J+2)-3 = J-1
Miriam is one year older than Joan: So, Miriam's age = J+1

The sum of all 4 ages = J + (J+2) + (J-1) + (J+1) = 4J+2

IMPORTANT: The sum of the ages is 2 more than some multiple of 4.
Scan the answer choices.
52 is a multiple of 4.
So, 54 is 2 more than some multiple of 4
Answer = D

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by GMATGuruNY » Tue Jun 16, 2015 8:12 am
j_shreyans wrote:Joan, Kylie, Lillian, and Miriam all celebrate their birthdays today. Joan is 2 years younger than Kylie, Kylie is 3 years older than Lillian, and Miriam is one year older than Joan. Which of the following could be the combined age of all four women today?

51

52

53

54

55
GmatKiss wrote:Joan, Kylie, Lillian, and Miriam all celebrate their birthdays today. Joan is 2 years younger than Kylie, Kylie is 3 years older than Lillian, and Miriam is one year older than Joan. Which of the following could be the combined age of all four women today?

· 51
· 52
· 53
· 54
· 55
The ages are all close together.
The answer choices imply that the sum of the 4 ages is between 51 and 55, inclusive.
Since 52/4 = 13, the average age must be around 13.

Let J=13.
Since Joan is 2 years younger than Kyle, K=15.
Since Kyle is 3 years older than Lillian, L=12.
Since Miriam is 1 year older than Joan, M=14.
Sum = 13+15+12+14 = 54.

The correct answer is D.

Algebra:

Let K = Kylie's age.
Since Joan is 2 years younger than Kylie, J = K-2.
Since Kylie is 3 years older than Lilian, L = K-3.
Since Miriam is 1 year older than Joan, M = (K-2) + 1 = K-1.

Sum of all four ages:
K + (K-2) + (K-3) + (K-1) = 4K - 6.
Implication:
The sum of the ages must be 6 less than a multiple of 4.

The smallest multiple of 4 greater than all of the answer choices is 60.
6 less than 60 = 60-6 = 54.
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by [email protected] » Tue Jun 16, 2015 9:24 am
Hi j_shreyans,

The first part of this question requires translating sentences into formulas:

J + 2 = K
L + 3 = K
J + 1 = M

Even if you translated these formulas differently, you still have a relationship among the 4 variables that needs to be discovered. You can TEST VALUES to figure out the relationship:

If K = 10, then
J = 8
L = 7
M = 9

Now we know that the 4 values are consecutive.

To solve, you can either use "brute-force" (since the answers are small) or algebra:

Brute-Force:
11 + 12 + 13 + 14 = 50 NOT ENOUGH BASED ON THE ANSWERS
12 + 13 + 14 + 15 = 54 WINNER

Algebra:
Call the youngest person X
X + (X+1) + (X+2) + (X+3) = 4X + 6
If X = 11, total = 50 NOT ENOUGH BASED ON THE ANSWERS
If X = 12, total = 54 WINNER

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by Matt@VeritasPrep » Tue Jun 23, 2015 7:18 pm
Rather than use variables, I might draw these out on some sort of number line, which is hard to show here, but which gives

Joan = Kylie - 2
Lilian = Kylie - 3
Miriam = Kylie - 1

So our sum = Kylie + (Kylie - 1) + (Kylie - 2) + (Kylie - 3), or 4K - 6. So the answer must be 6 less than a multiple of 4, meaning that 54 is the only possibility.