Hello guys,
Could you please help me with this?
5. The 4 sticks in a complete bag of Pick-Up Sticks are all straight-line segments of negligible width, but each has a different length: 1 inch, 2 inches, 3 inches, and 4 inches, respectively. If Tommy picks a stick at random from each of 3 different complete bags of Pick-Up Sticks, what is the probability that Tommy CANNOT form a triangle from the 3 sticks?
A. 11/32
B. 13/32
C. 15/32
D. 17/32
E. 19/32
Probability in forming a triangle
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First, determine total number of permutations = 4^3 or 64. Many of these are the same 3 numbers sequenced differently.
Clearly, there are 4 sequences of 1111-4444 > all of these meet the triangle rule of A+B>C, so 4 CANs
Sequences of 2 digits same, 3rd digit different: 112-114, 221,223-224, 331,332,334, 441-443: 12 sequence that have 3 permutations each equals 36 of 64. 24 of these meet triangle rule, so 24 CANs
Sequences of all 3 digits different: 123, 124, 134,234. 4 sequences with 6 permutations each equals 24 of 64. Only 234 meets triangle rule, with 6 permuations associated with it > 6 CANs
Adding up CANs equals 34, leaving 30/64 or 15/32 probability cannot form triangle
Answer C.
Clearly, there are 4 sequences of 1111-4444 > all of these meet the triangle rule of A+B>C, so 4 CANs
Sequences of 2 digits same, 3rd digit different: 112-114, 221,223-224, 331,332,334, 441-443: 12 sequence that have 3 permutations each equals 36 of 64. 24 of these meet triangle rule, so 24 CANs
Sequences of all 3 digits different: 123, 124, 134,234. 4 sequences with 6 permutations each equals 24 of 64. Only 234 meets triangle rule, with 6 permuations associated with it > 6 CANs
Adding up CANs equals 34, leaving 30/64 or 15/32 probability cannot form triangle
Answer C.