A committee of three students has to be formed. There are five candidates: Jane, Joan, Paul, Stuart, and Jessica. If Paul and Stuart refuse to be in the committee together and Jane refuses to be in the committee without Paul, how many committees are possible?
A. 3
B. 4
C. 5
D. 6
E. 8
OA later
Combination ques
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for the sake of convenience lets name Jane=A, Joan=B, Paul= C, Stuart =D and Jessica= Eselango wrote:A committee of three students has to be formed. There are five candidates: Jane, Joan, Paul, Stuart, and Jessica. If Paul and Stuart refuse to be in the committee together and Jane refuses to be in the committee without Paul, how many committees are possible?
A. 3
B. 4
C. 5
D. 6
E. 8
OA later
Combination possible are:
ABC, ACE, BDE, DEB. therefore 4 combinations. B
i hope i dint miss any.
Preet
- kvcpk
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You missed BCE. Answer should be 5singhpreet1 wrote:for the sake of convenience lets name Jane=A, Joan=B, Paul= C, Stuart =D and Jessica= Eselango wrote:A committee of three students has to be formed. There are five candidates: Jane, Joan, Paul, Stuart, and Jessica. If Paul and Stuart refuse to be in the committee together and Jane refuses to be in the committee without Paul, how many committees are possible?
A. 3
B. 4
C. 5
D. 6
E. 8
OA later
Combination possible are:
ABC, ACE, BDE, DEB. therefore 4 combinations. B
i hope i dint miss any.
Preet
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Jane refuses to be in the committee without Paulkvcpk wrote:You missed BCE. Answer should be 5singhpreet1 wrote:for the sake of convenience lets name Jane=A, Joan=B, Paul= C, Stuart =D and Jessica= Eselango wrote:A committee of three students has to be formed. There are five candidates: Jane, Joan, Paul, Stuart, and Jessica. If Paul and Stuart refuse to be in the committee together and Jane refuses to be in the committee without Paul, how many committees are possible?
A. 3
B. 4
C. 5
D. 6
E. 8
OA later
Combination possible are:
ABC, ACE, BDE, DEB. therefore 4 combinations. B
i hope i dint miss any.
Preet
therefore BCE is not possible buddy.
Preet
- amising6
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jane=jaselango wrote:A committee of three students has to be formed. There are five candidates: Jane, Joan, Paul, Stuart, and Jessica. If Paul and Stuart refuse to be in the committee together and Jane refuses to be in the committee without Paul, how many committees are possible?
joan=jo
paul=p
stuart=s
jessica=je
ja cant be with s
if p there then only ja will be there
now let select person on which there is no condition p,je will have to be 2 person,now e need to select third
p,je,ja
p,je,s
je,s,jo
p,jo,je
Ideation without execution is delusion
- kvcpk
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Jane refuses to be in the committee without Paulsinghpreet1 wrote:Jane refuses to be in the committee without Paulkvcpk wrote:You missed BCE. Answer should be 5singhpreet1 wrote:for the sake of convenience lets name Jane=A, Joan=B, Paul= C, Stuart =D and Jessica= Eselango wrote:A committee of three students has to be formed. There are five candidates: Jane, Joan, Paul, Stuart, and Jessica. If Paul and Stuart refuse to be in the committee together and Jane refuses to be in the committee without Paul, how many committees are possible?
A. 3
B. 4
C. 5
D. 6
E. 8
OA later
Combination possible are:
ABC, ACE, BDE, DEB. therefore 4 combinations. B
i hope i dint miss any.
Preet
therefore BCE is not possible buddy.
Preet
BUT
Paul doesnot refuse to be in the committee without Jane Buddy!!
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P and S can never be together. If there is no P, then there is no Jane. Thus, if there is Jane, then there is P.
P__ __
Here, we can't have S (because we have P). We can have any two of the three "J"s though. So that's 3 combinations so far.
S__ __
Here, we can't have P (because we have S). Because we don't have P, we also don't have Jane. That leaves only the other two Js. So, this is 1 more combination.
Can we have a committee with neither of P and S (ie, all 3 Js)? No, we can't. The moment we don't have P, we can't have Jane, and that would only leave the 2 other Js, and so we can't make the three-person committee.
Choose B.
P__ __
Here, we can't have S (because we have P). We can have any two of the three "J"s though. So that's 3 combinations so far.
S__ __
Here, we can't have P (because we have S). Because we don't have P, we also don't have Jane. That leaves only the other two Js. So, this is 1 more combination.
Can we have a committee with neither of P and S (ie, all 3 Js)? No, we can't. The moment we don't have P, we can't have Jane, and that would only leave the 2 other Js, and so we can't make the three-person committee.
Choose B.
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selango wrote:A committee of three students has to be formed. There are five candidates: Jane, Joan, Paul, Stuart, and Jessica. If Paul and Stuart refuse to be in the committee together and Jane refuses to be in the committee without Paul, how many committees are possible?
A. 3
B. 4
C. 5
D. 6
E. 8
OA later
A very good question, which tests how imaginative we really are. Let me call the five candidates: Jane, Joan, Paul, Stuart, and Jessica as A, B, C, D, and E respectively, just for simplicity.
Now, a committee with C cannot have D to it, hence the remaining two could be selected from three candidates in 3C2 = 3 ways. Case won't be same if the committee is constructed with D, as it won't have C to it and so A would also walk out. Now, the remaining two could be selected from two candidates in 2C2 = 1 way. Total ways are [spoiler]4, therefore.
B[/spoiler]
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Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
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www.manyagroup.com