Problem Solving

I had a question like this on the actual GMAT and not sure of the approach (or answer choices, so I apologize upfront).

The question went something like this:

A, B, C, D, E, and F are to be seated at a circular table. What is the probability that B sits between A and C, C between B and D, D between C and E, E between D and F, and F between A and E?

Also, are questions like this on the actual GMAT common? It seems like a toughie but I could be overthinking it. Thanks!

total nos of arrangements of 6 people on a circular table

is factorial (6-1)= factorial5= 120

nos of favourable arrangements=2
position fixed everybody (option of sitting either clockwise or anticlockwise direction)

hence probability is 2/120=1/60

wats the OA

i dont think its a difficult one

Probability of seating arrangements in circle is (n-1)!

selango wrote:Probability of seating arrangements in circle is (n-1)!

Nah!! Its the total Number of ways of seating arrangements= (N-1)!

Thanks for correcting my mistake