Question 1
All of the following are equal except:
A)2^20
B)2^19+2^19
C)4^10
D)4^5+4^5
E)16^5
Question 2
2√3+3√2
-------- =
√2
A)2+2√3
B)2+√6
C)2+3√6
D)3+2√3
E)3+√6
powers and roots
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Q1= B, you cant add exponents when you are adding
Q2=E , use the reciprocal to cancel out 2 sqrt 3 / sqrt 2 which equals sqrt 6. And 3sqrt2 / sqrt 2 cancels out to 3. So 3 + sqrt 6
Q2=E , use the reciprocal to cancel out 2 sqrt 3 / sqrt 2 which equals sqrt 6. And 3sqrt2 / sqrt 2 cancels out to 3. So 3 + sqrt 6
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algebraic simplification is required.luiscarlos59 wrote:Q1= B, you cant add exponents when you are adding
B) 2^19+2^19=2*(2^19)=2^(19+1)=2^20, this isn't correct answer.
the correct choice is d
4^5+4^5=2*4^5=2*2^10=2^(10+1)=2^11
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A)2^20klaud wrote:Question 1
All of the following are equal except:
A)2^20
B)2^19+2^19
C)4^10
D)4^5+4^5
E)16^5
B)2^19 + 2^19 = 2^19(1 + 1) = 2^19 * 2 = 2^20
C)4^10 = 2^20
D)4^5+4^5 = 2^10 + 2^10 = 2^10(1 + 1) = 2^11
E)16^5 = (2^4)^5 = 2^20
Only [spoiler](D)[/spoiler] is not equal to other answer choices.
The correct answer is D.
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Multiply the numerator and denominator of given fraction by √2,Question 2
2√3+3√2
-------- =
√2
A)2+2√3
B)2+√6
C)2+3√6
D)3+2√3
E)3+√6
(2√3 + 3√2)/√2 = √2(2√3 + 3√2)/(√2)(√2) = [2√6 + 3(√2)(√2)]/2 = [2√6 + 6]/2 = √6 + 3
The correct answer is E.
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