Solve
If x and y are non-zero integers, and 9x^4 – 4y^4 = 3x^2 + 2y^2, which of the following could be the value of x^2 in terms of y?
Answer choices
-4y^2/3
-2y^2
(2y^2+1)/3
2y^2
6y^2/3
exponents x & y fun
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- Master | Next Rank: 500 Posts
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Nicely done, the trick here is to realize the difference of squares eqn canDelpaiero wrote:From 9x^4-4y^4=3x^2+2y^2
then (3x^2-2y^2)(3x^2+2y^2) = 3x^2+2y^2
(3x^2-2y^2) = 1
x^2 = (1+2y^2)/3
Good luck!!!!
be made.