If \(w, y\), and \(z\) are positive integers, and

This topic has expert replies
Legendary Member
Posts: 2231
Joined: Sun Oct 29, 2017 2:04 pm
Followed by:6 members

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

If \(w, y\), and \(z\) are positive integers, and \(w = y - z\), is \(w\) a perfect square?

1) \(y + z\) is a perfect square.
2) \(z\) is even.

The OA is E

Source: Manhattan Prep

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 3008
Joined: Mon Aug 22, 2016 6:19 am
Location: Grand Central / New York
Thanked: 470 times
Followed by:34 members

by Jay@ManhattanReview » Thu Apr 25, 2019 9:17 pm

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

swerve wrote:If \(w, y\), and \(z\) are positive integers, and \(w = y - z\), is \(w\) a perfect square?

1) \(y + z\) is a perfect square.
2) \(z\) is even.

The OA is E

Source: Manhattan Prep
The optimum approach would be to test values.

Given: \(w, y\), and \(z\) are positive integers, and \(w = y - z\)

We have to find out whether \(w\) is a perfect square.

Let's take each statement one by one.

1) \(y + z\) is a perfect square.

Case 1: Say y = 5 and z = 4. We see that y + z = 5 + 4 = 9, a perfect square and w = y - z = 5 -4 = 1, a perfect square. The answer is yes.
Case 2: Say y = 7 and z = 2. We see that y + z = 7 + 2 = 9, a perfect square but w = y - z = 7 - 2 = 5, NOT a perfect square. The answer is no.

No unique answer. Insufficient.

2) \(z\) is even.

No information about w and y. Both the cases discussed in Statement 1 are applicable here, too. Insufficient.

(1) and (2) together

Both the cases discussed in Statement 1 are applicable here, too. Insufficient.

The correct answer: E

Hope this helps!

-Jay
_________________
Manhattan Review GMAT Prep

Locations: GRE Manhattan | TOEFL Prep Courses San Diego | IELTS Prep Courses Denver | San Francisco ACT Tutoring | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.