Source: GMAT Prep
The figure shown represents a board with 4 rows of pegs, and at the bottom of the board are 4 cells numbered 1 to 4. Whenever the ball showed passes through the opening between two adjacent pegs in the same row, it will hit the peg directly beneath the opening. The ball then has the probability 1/2 of passing through the opening immediately to the left of that peg and probability 1/2 of passing through the opening immediately to the right. What is the probability that when the ball passes through the first two pegs at the top it will end in Cell 2?
A. 1/16
B. 1/8
C. 1/4
D. 3/8
E. 1/2
The OA is D
The figure shown represents a board with 4 rows of pegs, and
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- Jay@ManhattanReview
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So, there are three ways by which the ball can go in Cell 2. If the ball goes...BTGmoderatorLU wrote:Source: GMAT Prep
The figure shown represents a board with 4 rows of pegs, and at the bottom of the board are 4 cells numbered 1 to 4. Whenever the ball showed passes through the opening between two adjacent pegs in the same row, it will hit the peg directly beneath the opening. The ball then has the probability 1/2 of passing through the opening immediately to the left of that peg and probability 1/2 of passing through the opening immediately to the right. What is the probability that when the ball passes through the first two pegs at the top it will end in Cell 2?
A. 1/16
B. 1/8
C. 1/4
D. 3/8
E. 1/2
The OA is D
1. Left --> Left --> Right; probability = 1/2*1/2*1/2 = 1/8;
2. Left --> Right --> Right; probability = 1/2*1/2*1/2 = 1/8;
3. Right --> Left --> Left; probability = 1/2*1/2*1/2 = 1/8
Total probability = 1/8 + 1/8 + 1/8 = 3/8
The correct answer: D
Hope this helps!
-Jay
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Let L denote the event that the ball hits a peg and passes through the left opening and R denotes the event that the ball hits a peg and passes through the right opening. The routes that end at the second bin are L - L - R, L - R - L and R - L - L. Notice that each of these routes have a probability of 1/2 x 1/2 x 1/2 = 1/8 and since there are three such routes, the overall probability that the ball ends up in the second bin is 3 x 1/8 = 3/8.BTGmoderatorLU wrote:Source: GMAT Prep
The figure shown represents a board with 4 rows of pegs, and at the bottom of the board are 4 cells numbered 1 to 4. Whenever the ball showed passes through the opening between two adjacent pegs in the same row, it will hit the peg directly beneath the opening. The ball then has the probability 1/2 of passing through the opening immediately to the left of that peg and probability 1/2 of passing through the opening immediately to the right. What is the probability that when the ball passes through the first two pegs at the top it will end in Cell 2?
A. 1/16
B. 1/8
C. 1/4
D. 3/8
E. 1/2
The OA is D
Answer: D
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