In the rectangular coordinate system above, the area of tria

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In the rectangular coordinate system above, the area of triangular region PQR is

(A) 12.5
(B) 14
(C) 10√2
(D) 16
(E) 25

OA A

Source: GMAT Prep

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BTGmoderatorDC wrote:Image

In the rectangular coordinate system above, the area of triangular region PQR is

(A) 12.5
(B) 14
(C) 10√2
(D) 16
(E) 25
Source: GMAT Prep
Image

\[? = {S_{{\text{rectangle}}}} - \left( {{S_1} + {S_2} + {S_3}} \right)\]
\[\left. \begin{gathered}
{S_{{\text{rectangle}}}}\,\, = \,\,7 \cdot 4\,\, = \,\,28\,\,\, \hfill \\
{S_1}\,\, = \,\,\frac{{4 \cdot 3}}{2}\,\, = \,\,6 \hfill \\
{S_2}\,\, = \,\,\frac{{3 \cdot 4}}{2}\,\, = \,\,6 \hfill \\
{S_3}\,\, = \,\,\frac{{7 \cdot 1}}{2}\,\, = \,\,3.5 \hfill \\
\end{gathered} \right\}\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,?\,\,\, = \,\,\,12.5\]


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by Brent@GMATPrepNow » Thu Jan 24, 2019 6:01 am
BTGmoderatorDC wrote:Image

In the rectangular coordinate system above, the area of triangular region PQR is

(A) 12.5
(B) 14
(C) 10√2
(D) 16
(E) 25

OA A

Source: GMAT Prep
Let's draw a rectangle around the triangle (as shown below) and then subtract from the rectangle's area (28) the areas of the 3 right triangles that surround the triangle in question.

We get the following:
Image

So, the area of PQR = 28 - (3.5 + 6 + 6) = 12.5

Answer: A

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Brent
Brent Hanneson - Creator of GMATPrepNow.com
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