A square garden is surrounded by a path of uniform width. If the path and the garden both have an area of x, then what is the width of the path in terms of x?
$$\text{A. } x\sqrt{2}$$
$$\text{B. } 2\sqrt{x}-\sqrt{2}$$
$$\text{C. } \frac{\sqrt{2}}{2}-\frac{x}{4}$$
$$\text{D. } x\sqrt{2}-\frac{x}{2}$$
$$\text{E. } \frac{\sqrt{2x}}{2}-\frac{\sqrt{x}}{2}$$
The OA is E
Source: Magoosh
A square garden is surrounded by a path of uniform width. If
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Say the length of the width = wswerve wrote:A square garden is surrounded by a path of uniform width. If the path and the garden both have an area of x, then what is the width of the path in terms of x?
$$\text{A. } x\sqrt{2}$$
$$\text{B. } 2\sqrt{x}-\sqrt{2}$$
$$\text{C. } \frac{\sqrt{2}}{2}-\frac{x}{4}$$
$$\text{D. } x\sqrt{2}-\frac{x}{2}$$
$$\text{E. } \frac{\sqrt{2x}}{2}-\frac{\sqrt{x}}{2}$$
The OA is E
Source: Magoosh
Area of the path = Area of the path incl. garden - Area of the garden
x = Area of the path incl. garden - x
Area of the path incl. garden = 2x
Area of the path incl. garden = (length of the garden + 2*width of the path)^2
Length of the garden = Square root of the area of the garden = Square root of x
Length of the garden = √x
Thus, the area of the path incl. garden = (√x + 2w)^2
=> 2x = (√x + 2w)^2
√2.√x = √x + 2w
2w = √2.√x - √x
=> w = √2x/2 - √x/2
The correct answer: E
Hope this helps!
-Jay
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Since the square garden has an area of x, its side length is √x. Since the square garden is surrounded by a path of uniform width, the shape of the path and garden combined is also a square. We can let the width of the path = n, and thus the side length of the square that is the path and garden combined is √x + 2n. Since the total area of the path and garden is x + x = 2x, we have:swerve wrote:A square garden is surrounded by a path of uniform width. If the path and the garden both have an area of x, then what is the width of the path in terms of x?
$$\text{A. } x\sqrt{2}$$
$$\text{B. } 2\sqrt{x}-\sqrt{2}$$
$$\text{C. } \frac{\sqrt{2}}{2}-\frac{x}{4}$$
$$\text{D. } x\sqrt{2}-\frac{x}{2}$$
$$\text{E. } \frac{\sqrt{2x}}{2}-\frac{\sqrt{x}}{2}$$
The OA is E
Source: Magoosh
(√x + 2n)^2 = 2x
Taking the square root of both sides, we have:
√x + 2n = √(2x)
2n = √(2x) - √x
n = √(2x)/2 - √x/2
Answer: E
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