If x, y and z are different integers, what is the value of y?
1) The average (arithmetic mean) of x, y and z is 2
2) x<y<z
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If x, y and z are different integers, what is the value of y
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BTGmoderatorDC
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BTGmoderatorDC wrote:If x, y and z are different integers, what is the value of y?
1) The average (arithmetic mean) of x, y and z is 2
2) x<y<z
GMAT/MBA Expert
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Jay@ManhattanReview
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BTGmoderatorDC wrote:If x, y and z are different integers, what is the value of y?
1) The average (arithmetic mean) of x, y and z is 2
2) x<y<z
GMAT/MBA Expert
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Jay@ManhattanReview
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Given: x, y and z are different integersBTGmoderatorDC wrote:If x, y and z are different integers, what is the value of y?
1) The average (arithmetic mean) of x, y and z is 2
2) x<y<z
Question: What is the value of y?
Let's take each statement one by one.
1) The average (arithmetic mean) of x, y and z is 2.
=> x + y + z = 6. Insufficient.
2) x < y < z
Insufficient.
(1) and (2) together
There are can be many combinations of x, y, and z keeping the three conditions: 1). x + y + z = 6 and 2). x < y < z 3). x, y and z are different integers
For example: 1). x = 0, y = - 4 and z = 10; 2). x = 1, y = -5 and z = 10. No unique value of y.
The correct answer: E
Hope this helps!
-Jay
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deloitte247
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What is the value of x
Statement 1 = The average (arithmetic mean) of x, y and z is 2.
This means that the sum of the 3 integers is 6
$$\frac{Efx}{f}=\ \frac{\left(x+y+2\right)}{3}$$
With this we have multiple solutions because,
$$\frac{\left(0+1+5\right)}{3}=\ \frac{6}{3}=2$$
$$\frac{\left(2+2+2\right)}{3}=\ \frac{6}{3}=2$$ $$\frac{\left(1+2+3\right)}{3}=\ \frac{6}{3}=2$$
Hence, statement 1 is NOT SUFFICIENT.
Statement 2 = x
From my own view, there is no sufficient information on about y and z,
Hence, statement 2 is NOT SUFFICIENT.
Therefore, statement 1 and 2 are both not sufficient, hence leaving us with option E as the correct answer.
Statement 1 = The average (arithmetic mean) of x, y and z is 2.
This means that the sum of the 3 integers is 6
$$\frac{Efx}{f}=\ \frac{\left(x+y+2\right)}{3}$$
With this we have multiple solutions because,
$$\frac{\left(0+1+5\right)}{3}=\ \frac{6}{3}=2$$
$$\frac{\left(2+2+2\right)}{3}=\ \frac{6}{3}=2$$ $$\frac{\left(1+2+3\right)}{3}=\ \frac{6}{3}=2$$
Hence, statement 1 is NOT SUFFICIENT.
Statement 2 = x
From my own view, there is no sufficient information on about y and z,
Hence, statement 2 is NOT SUFFICIENT.
Therefore, statement 1 and 2 are both not sufficient, hence leaving us with option E as the correct answer.
