Please help me with this!!!! Thanks in advance.
If 2^6 < x < 2^8, is x closer to 2^6 or 2^8 ?
1. x is closer to 2^4 than to 2^9
2. x is closer to 2^5 than to 2^7
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sudhir3127
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IMO Dalsergi wrote:Please help me with this!!!! Thanks in advance.
If 2^6 < x < 2^8, is x closer to 2^6 or 2^8 ?
1. x is closer to 2^4 than to 2^9
2. x is closer to 2^5 than to 2^7
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niraj_a
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B
ok so 2^6 = 64 and 2^ 8 = 256 (i calculated it out, wasnt that hard if you know 2^3 = 8 as a starting point)
now, the midpoint of this range is = (256+64)/2 = 160. so we can assume that we have to find if X is lower than 160.
Statement I
2^4 = 16 2^9 = 512
midpoint = (512+16)/2 = 264
Insufficient because X could be anywhere between 160 and 264.
Sattement II
2^5 = 32 2^7 = 128
midpoint = (128+32)/2 = 80
Sufficient because X is now definitely below 160.
Alternative explanation -
I solved this quickly at first by finding that the range was way too big in Statement I vs. Statement II, so I chose B in the end. Then I calculated the mid-points etc. to be able to post in this thread.
Would love to know if B is correct.
ok so 2^6 = 64 and 2^ 8 = 256 (i calculated it out, wasnt that hard if you know 2^3 = 8 as a starting point)
now, the midpoint of this range is = (256+64)/2 = 160. so we can assume that we have to find if X is lower than 160.
Statement I
2^4 = 16 2^9 = 512
midpoint = (512+16)/2 = 264
Insufficient because X could be anywhere between 160 and 264.
Sattement II
2^5 = 32 2^7 = 128
midpoint = (128+32)/2 = 80
Sufficient because X is now definitely below 160.
Alternative explanation -
I solved this quickly at first by finding that the range was way too big in Statement I vs. Statement II, so I chose B in the end. Then I calculated the mid-points etc. to be able to post in this thread.
Would love to know if B is correct.
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kuroneko1313
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stubbornp
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niraj_a wrote:B
ok so 2^6 = 64 and 2^ 8 = 256 (i calculated it out, wasnt that hard if you know 2^3 = 8 as a starting point)
now, the midpoint of this range is = (256+64)/2 = 160. so we can assume that we have to find if X is lower than 160.
Statement I
2^4 = 16 2^9 = 512
midpoint = (512+16)/2 = 264
Insufficient because X could be anywhere between 160 and 264.
Sattement II
2^5 = 32 2^7 = 128
midpoint = (128+32)/2 = 80
Sufficient because X is now definitely below 160.
Alternative explanation -
I solved this quickly at first by finding that the range was way too big in Statement I vs. Statement II, so I chose B in the end. Then I calculated the mid-points etc. to be able to post in this thread.
Would love to know if B is correct.
Answer should be D....
How you can take mide point of statements values....
x is unique as in stimulus...
Yes, definitely the right answer is B. Thank you all !!!!
alsergi wrote:Please help me with this!!!! Thanks in advance.
If 2^6 < x < 2^8, is x closer to 2^6 or 2^8 ?
1. x is closer to 2^4 than to 2^9
2. x is closer to 2^5 than to 2^7
